**Problem 5:**A box with mass \( m = 71 \, \text{kg} \) is being pulled by a constant force \( F = 150 \, \text{N} \) at an angle of \( \theta = 29 \, \text{degrees} \). The initial speed of the box is zero.*Diagram Description:*The diagram depicts a box labeled \( M \) on a flat surface. A force \( F \) is applied at an angle \( \theta \) to the horizontal axis \( x \).**Part (a):** *Write an expression for the work done by force \( F \) as the block moves a horizontal distance \( d \).***Expression:**\[ W = \text{_______________________________________________} \]Select from the variables below to write your expression. Note that all variables may not be required.\[ \cos(\alpha), \cos(\varphi), \cos(\theta), \sin(\alpha), \sin(\varphi), \sin(\theta), \alpha, \beta, \theta, d, F, g, h, j, m, P, t, \tan(\alpha), \tan(\varphi), \tan(\theta) \]**Part (b):***How much work, in joules, was done in moving the block 5.6 m?***Numeric:**A numeric value is expected and not an expression.\[ W = \text{_______________________________________________} \]**Part (c):***What is the speed of the box at \( d = 5.6 \, \text{m} \) if the surface is frictionless?***Numeric:**A numeric value is expected and not an expression.\[ v_d = \text{______________________________________________} \]

Name: **Problem 5:**A box with mass \( m = 71 \, \text{kg} \) is being pull
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: **Problem 5:**A box with mass \( m = 71 \, \text{kg} \) is being pulled by a constant force \( F = 150 \, \text{N} \) at an angle of \( \theta = 29 \, \text{degrees} \). The initial speed of the box is zero.*Diagram Description:*The diagram depicts

mass, m = 71 kg force, F = 150 N distance, d = 5.6m angle, θ = 29°

Answered: Problem 5: A box m = 71 kg is being…

Science

Physics

Problem 5: A box m = 71 kg is being pulled by a constant force F = 150 N at an angle of 0 = 29 degrees. The initial speed of the box is zero. y F M

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A machine carries a 8.0 kg package from an initial position of d ; = (0.6 m) i + (0.79 m)j + (0.26…

A: Given: di=0.6m i^ + 0.79m j^ + 0.26m k^df=10.5m i^ + 15.0m j^ + 10.2m k^∆t = 15 sF = 4.0N i^ +7.0N…

Q: A 1000 kg automobile is moving at 30 m/s at a height of 5.0 m above the bottom of a hill when it…

A: Mass ( m ) = 1000 kg Height ( hi ) = 5 meter Velocity ( uf ) = 30 m/s

Q: A force F = (cx - 3.00x2)î acts on a particle as the particle moves along an x axis, with F in…

A: Work-energy theorem states that the work done by the sum of all forces acting on a particle equals…

Q: An object is thrown with an initial speed of 15 m/s at an angle of 35.0 degrees above the horizontal…

A: Given: The intial speed of the object is 15 m/s. The angle of the projection is 15o. The height of…

Q: which height will

Q: A daredevil on a motorcycle leaves the end of a ramp with a speed of 38.9 m/s as in the figure…

A: KEBottom-KEtop=PE0.5mvbottom2-0.5mvtop2=mghh=0.vbottom2-0.5vtop2g

Q: A 9.5 kg block is forced against a horizontal spring, compressing the spring 0.3 m. When released,…

Q: by strings to a vertical, rotating rod. The strings a e upper string is 24.0 cm long and has a…

A: Centripetal force = mv2 /r

Q: A 60.0 kg skier with an initial speed of 12.0 m/s coasts up a 2.50 m high rise as shown above. Find…

A: Given

Q: A 60.0 kg skier with an initial speed of 15 m/s coasts up a 2.50 m high rise as shown in the figure.…

A: The objective of this question is to find the final speed of the skier at the top of the slope. We…

Q: *Chapter 8, Problem 62 In the figure a block slides along a path that is without friction until the…

A: Speed at point b V = 10.18 m/s

Q: A 4.0 kg block starts with a speed of 15 m/s at the bottom of a plane inclined at 33° to the…

Q: box with mass m goes down a ramp that makes an angle of 60 º with the horizontal. The ramp bands…

Q: You and your friends push a 400 kg piano across a hardwood floor at a constant speed. You all push…

Q: 8. A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x0.…

A: Solution:- Determine the function y at x =2.36 m.…

Q: The figure below shows a block of mass 0.5 kg moving on the inside surface of a vertical circular…

A: Workdone by gravity on the block as it slides to the top of the loop, W_gravity = -m*g*(2*R) =…

Q: デジタル形式で段階的に解決ありがとう!! SOLVE STEP BY STEP IN DIGITAL FORMAT An engine consumes 40.0 hp to propel a…

A: The retarding force is 1.99 kNExplanation:Given:Power, P = 40 hpVelocity, v = 15.0 m/s To find:…

Q: Please help

A: Please see the attached image for the solution.If there are queries or if the image is not loading,…

Q: In the figure, a 3.7 kg block slides along a track from one level to a higher level after passing…

Q: In the figure, a 4.1 kg block slides along a track from one level to a higher level after passing…

Q: A curling stone has a mass of 18.0 kg. The stone begins initially at rest on a flat ice surface. It…

A: Given data: Mass (m) = 18.0 kg Constant Force (F) = 24.0 N Distance (d) = 4.00 m Required: The…

Q: m h2 h1

A: mass of block (m) = 10 kg Distance along the flat muddy section (d) = 1 m coefficient of kinetic…

Q: A stone with a weight of 5.34 N is launched vertically from ground level with an initial speed of…

Q: box is placed at the top of an incline at an angle 21.8 degrees to the horizontal. When released the…

Q: A 3kg block slides along a floor with coefficient of kinetic friction μk=0.3, initially moving at…

Concept explainers

Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

Topic Video

Question

**Problem 5:**

A box with mass \( m = 71 \, \text{kg} \) is being pulled by a constant force \( F = 150 \, \text{N} \) at an angle of \( \theta = 29 \, \text{degrees} \). The initial speed of the box is zero.

*Diagram Description:*

The diagram depicts a box labeled \( M \) on a flat surface. A force \( F \) is applied at an angle \( \theta \) to the horizontal axis \( x \).

**Part (a):**

*Write an expression for the work done by force \( F \) as the block moves a horizontal distance \( d \).*

**Expression:**

\[ W = \text{_______________________________________________} \]

Select from the variables below to write your expression. Note that all variables may not be required.

\[ \cos(\alpha), \cos(\varphi), \cos(\theta), \sin(\alpha), \sin(\varphi), \sin(\theta), \alpha, \beta, \theta, d, F, g, h, j, m, P, t, \tan(\alpha), \tan(\varphi), \tan(\theta) \]

**Part (b):**

*How much work, in joules, was done in moving the block 5.6 m?*

**Numeric:**

A numeric value is expected and not an expression.

\[ W = \text{_______________________________________________} \]

**Part (c):**

*What is the speed of the box at \( d = 5.6 \, \text{m} \) if the surface is frictionless?*

**Numeric:**

A numeric value is expected and not an expression.

\[ v_d = \text{______________________________________________} \]

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A ball of mass 0.5kg is tied to a string of length 1.0 meters, and the other end of the string is tied to a rigid support. The ball is held straight out horizontally and is then released. a) What is the speed of the ball at the lowest point of its motion? b) What is the tension in the string at its joint? Solution FBD and Formula Required
A piece of ice (m = 1 Kg) slides down the slope of a roof inclined at 50.0°. It starts from rest and slides 8.0 m along the roof, sliding off the edge at a height of 4.0 m above the level ground. The coefficient of kinetic friction is 0.14. V¡ = 0.0 m/s m = 500.0 g 8,0 m Hx = 0.14 30° 4.0 m (a) Draw a free-body diagram of the ice as it is sliding along the roof. (b) Calculate the acceleration of the object. (c)With what speed does it leave the roof?
A skier weighing 0.85 kN goes over a frictionless circular hill as shown. If the skier's speed at point A is 8.8 m/s, what is his speed at the top of the hill (point B)?
A 02 UBC Engineering A trapeze artist of a mass of M to 01 trick. If the ropes do NO work on the artist, what is the speed just before they let go? What is their normal acceleration? 79kg is attempting a new trick on a rope of l 70° and then rope A is cut. The artist holds on until when 02 = 15° then lets go for the next 15m. They are lifted Neglect size and air resistance
A block slides along a track with an initial velocity vo = 7.0 m/s from one level to a higher level after passing through an intermediate valley. The difference h from the initial position to the elevated track is 0.89 m. The track is frictionless until reaches the top. There (at the top), a frictional force stops the block in a distance d. The coefficient of kinetic friction between the block and the surface is 0.60. Find the distance d.
A 4.00kg block moves with an initial speed of3.50 km/h downhillover an inclined plane as shown in the figure. The height of the inclined plane is 51.3cm and the friction coefficient between the block and the incline is 0.120. a.How much is the speed of the block at the midpoint of the inclined side. b.How much is the speed of the block at the bottom of the inclined side.
A 13.0kg stone slides down an icy, essentially frictionless, hill that is shown in the figure. At the top of the hill, the stone is moving at 1.75m/s down the hill. While the hill is frictionless, the stone experiences friction along the level, rough ground (beyond the base of the hill) all the way to a wall. The coefficients of static and kinetic friction are 0.800 and 0.300 respectively. The stone slides along the ground for 9.15m before making contact with a long spring, which has a spring constant of 25.0N/m. (“Long” in this case means that the spring is sufficiently long to stop the stone before it hits the wall.) Will the stone move again after it has been stopped by the spring?
A 60.0 kg skier with an initial speed of 14 m/s coasts up a 2.50 m high rise as shown in the figure. Find her final speed right at the top, in meters per second, given that the coefficient of friction between her skis and the snow is 0.39.
10. Block 1 with a mass of 1.0 kg slides down a frictionless ramp with a height of 3.0 m and cllides with block 2 which has a mass of 2.0 kg. The flat surface has friction with a friction coefficient of 0.50. 2 a. Determine the speed of block 1 when it reaches the bottom of the ramp.
A 9.0-kg bunny slides from rest down a frictionless incline from a height of 5.0 m. A constant frictional force, introduced at point A, brings the bunny to rest at point B, 19 m to the right of point A. What is the Speed of the bunny before it reaches point A? What is the coefficient of kinetic friction, µk, of the surface from A to B?
A3
A 4.25 kg block is projected at 5.40 m/s up a plane that is inclined at 30.0° with the horizontal. The block slides some distance up the incline, stops turns around and slides back down to the bottom. When it reaches the bottom of the incline again, it is traveling with a speed of 3.80 m/s. If the coefficient of kinetic friction between the block and the plane is 0.500, how far up the incline did the block slide?