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Problem 4. A tube 1 cm in inside diameter that is 20 cm long is filled with CO2 and H2 at a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2-H2 system under these conditions is 0.275 cm2/sec. If the partial pressure of CO2 is 1.5 atm at one end of the tube and 0.5 atm at the other end, find the rate of diffusion for the following cases:

Problem 4. A tube 1 cm in inside diameter that is 20 cm long is filled with CO2 and H2 at a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2-H2 system under these conditions is 0.275 cm2/sec. If the partial pressure of CO2 is 1.5 atm at one end of the tube and 0.5 atm at the other end, find the rate of diffusion for the following cases:

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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Problem 4. A tube 1 cm in inside diameter that is 20 cm long is filled with CO2 and H2 at a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2-H2 system under these conditions is 0.275 cm2/sec. If the partial pressure of CO2 is 1.5 atm at one end of the tube and 0.5 atm at the other end, find the rate of diffusion for the following cases: i) Steady state equimolar counter diffusion (N A = - N B) ii) Steady state counter diffusion where N B = -0.75 N A, and iii) Steady state diffusion of CO2 through stagnant H2 (NB = 0) *
Transcribed Image Text:Problem 4. A tube 1 cm in inside diameter that is 20 cm long is filled with CO2 and H2 at a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2-H2 system under these conditions is 0.275 cm2/sec. If the partial pressure of CO2 is 1.5 atm at one end of the tube and 0.5 atm at the other end, find the rate of diffusion for the following cases: i) Steady state equimolar counter diffusion (N A = - N B) ii) Steady state counter diffusion where N B = -0.75 N A, and iii) Steady state diffusion of CO2 through stagnant H2 (NB = 0) *
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