Problem #4: The manager at a clothing store would like to compare the sales of two employees, Employee A and Employee B.The daily sales (in S) for the two employees are recorded for random sample of days and some summary statisticsare below:Problem #4(a):Problem #4(b):Problem #4(c):nXDOZAА 7 1515 419111199BS202We assume that the daily sales of each employee is normally distributed and they share a common variance.(a) What is the estimate of the common variance of their daily sales?(b) What is the critical value if we wish to conduct a test at 5% level of significance to determine if there is adifference in their true mean daily sales?(c) What is the p-value of the test?answer correct to 2 decimalsanswer correct to 3 decimalsanswer correct to 4 decimals

We have given that, X1 = 1515n1 = 7S1 = 419X2 = 1199n2 = 11S2 = 202Alpha = 0.05(a) Pooled…

Answered: Problem #4: The manager at a clothing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Problem 6 – Assume that the population is approximately distributed. The Department of Labor and Employment reported that a person between the ages of 20 and 40 has had an average of 9.2 jobs. To see if this average is correct, a statistician selected a sample 8 employees between the ages of 20 and 40 and asked how many different companies they had been employed. The results are shown below: 8 12 15 6 1 9 13 2 At a = 0.05, can it be concluded that the mean is 9.2? Use the P-value method. Also, give one reason why the number of respondents might not have given the exact number of jobs that they have been employed.
QUESTION 4 The Global Business Travel Association (GBTA) reported the domestic airfare for business travel for the current year and the previous year. Below is a sample of 6 flights with their domestic airfares (in $) shown for both years. Suppose GBTA wished to see if the average airfare for the current year is greater than the average airfare for the previous year at a=.1. Current 355 743 560 449 263 651 Previous 348 746 549 440 250 652 For the hypothesis stated above, what is the critical value (in terms of "Current" minus "Previous")? O a. 1.476 O b. 1.440 O C. 1.383 O d. None of the answers is correct O e. 1.372 QUESTION 5 Sav Click Save and Submit to save and submit. Click Save All Answers to save all answers. MacBook Pro
Problem 2: The research scenario: Do you think there might be a relationships between people's personality and the profession they pursue? Here's a fictional set of data that explores that question. There are two personality types in the data, 'thinkers' and 'feelers.' There are 3 professions. A chi square analysis says, OK, there is a certain proportion of people who are thinkers overall (you will be calculating that, but is comes directly from the data). Is that same proportion (or close to it) found among each of the three professions? For example, if the population at large is divided into 50% thinkers and 50% feelers, then 50% of each profession would be thinkers and 50% would be feelers. But maybe some professions have 'lopsided' percentages of feelers, or lopsided percentages of thinkers. The following crosstab table shows the "crossed" frequencies for 2 variables: "Myers-Brigg" personality type "T" = "thinking" personality…
Problem #4: Consider the data set that is summarized in the R Output below. leaf unit: 1 n: 13 422 4 (6) 3- 1 0 2 7 3 4 5 6 677 37 334788 (a) Find the values of Q₁ and Q3. (b) Find the median (c) Find the adjacent values. (Note: Read this file for the relevant definitions, and for an example.)
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Help me answer these problems : One-way ANOVA Provide the ANOVA Table for each problem. An example ANOVA table is presented below:
EXAMPLE 3.20 Suppose a study of speeding violations and drivers who use cell phones produced the following fictional data: Uses cell phone while driving Does not use cell phone while driving Total Table 3.2 Speeding violation in the last year 25 45 70 No speeding violation in the last year 280 405 685 Total Problem a. Find P(Driver is a cell phone user). b. Find P(Driver had no violation in the last year). c. Find P(Driver had no violation in the last year was a cell phone user). d. Find P(Driver is a cell phone user U driver had no violation in the last year). e. Find P(Driver is a cell phone user driver had a violation in the last year). 1. Find P(Driver had no violation last year driver was not a cell phone user) 305 450 *** 755 The total number of people in the sample is 755. The row totals are 305 and 450. The column totals are 70 and 685. Notice that 305 + 450 = 755 and 70 +685 755. Calculate the following probabilities using the table.
Problem 1. A Chemical engineer wants to analyze the Level of Chemical Concentration (LCC) in two main areas of a city. The following data of the Level of Chemical Concentration for a period of 15 days are collected. Day: 1 2 3 4 5 7 8 9. 10 11 12 13 14 15 Area A: 9 9. 8. 4 4 9 2 2 2 1 Area B: 7 7 5 4 3 2 0 9. 2 8 1 Find: a) Mean of the data b) Variance of the data c) Mode of the data d) Standard deviation of the data f) Draw the comparative boxplots of the data e) Median of the data g) Draw the line plot of the data h) What can you conclude?
QUESTION FIVE: a) Explain in general the importance of measures of central tendency, measures of variation and measures of normality in business decision making. b) The table below shows the frequency distribution for the number of minutes per week spent watching TV by residents of Nyali in Mombasa. Viewing Time (minutes) 300-399 Number of Residents 14 400-499 46 500-599 58 600-699 76 700-799 800-899 68 62 900-999 48 1000-1099 22 1100- 1199 6. Total 400 Required: By calculating the Mean, Mode, Median, Standard Deviation and First and Second Pearsonian Moment Coefficients of Skewness comment on the Skewness of the distribution. Assuming the distribution approximates a Normal Distribution what proportion of the residents: ii. a) Spend less than 480 hours watching television b) Spend between 725 and 1025 hours watching television. c) Spend more than 800 hours watching television.

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