Problem 4 Review I Cc For the reaction 2CO (g) +02(g) = 2CO 2 (g ) , the equilibrium concentrations at a certain temperature are [CO2] = 0.10 mol/L, [02] = 1.7x102 mol/L, [CO] - 2.4x102 mol/L. Part B What is the value of Kat this temperature? Express your answer using two significant figures. ΑΣφ ? K = 25 Previous Answers Request Answer Submit x Incorrect; Try Again; 5 attempts remaining Part C Are reactants or products favored? P Pearson 2019 Pearson Education Inc. All rights reserved. | Terms of UseI Privacy Policy Permissions Contact Us Copyright

Problem 4 Review I Cc For the reaction 2CO (g) +02(g) = 2CO 2 (g ) , the equilibrium concentrations at a certain temperature are [CO2] = 0.10 mol/L, [02] = 1.7x102 mol/L, [CO] - 2.4x102 mol/L. Part B What is the value of Kat this temperature? Express your answer using two significant figures. ΑΣφ ? K = 25 Previous Answers Request Answer Submit x Incorrect; Try Again; 5 attempts remaining Part C Are reactants or products favored? P Pearson 2019 Pearson Education Inc. All rights reserved. | Terms of UseI Privacy Policy Permissions Contact Us Copyright

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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QUESTION 17 CEINTEISEBLEN STEE Consider the reaction: XeF2 (g) + F2 (g) = XeF4 (g) From which of the following starting composition(s) is it impossible to establish the equilibrium condition for the reaction above? O A. 0.25 mol XeF2 (g) O B. 0.25 mol F2 (g) and 0.25 mol XeF4 (g) O c.0.25 mol XeF4 (g) O D. 0.25 mol XeF2 (g) and 0.25 mol F2 (g) O E. 0.25 moi XeF2 (g) and 0.25 mol XeF4 (g)
Exercises 39. Consider the reaction: MISSED THIS? Read Section 16.8; Watch IWE 16.8 2 NO(g) + Br2(8)=2 NOB1(g) In a reaction mixture at equilibrium, the partial pressure of NO is 108 torr and that of Br, is 126 torr. What is the partial pressure К, — Kp 28.4 at 298 K of NOB in this mixture?
3.3 The following diagram represents the equilibrium state for the reaction: A2 (g) + 2 B (g) 2 AB (g) Key A2 00 АВ a) Assuming the volume is 1 dm', calculate the equilibrium constant for the reaction. b) If the volume of the equilibrium mixture is decreased, will the number of AB molecules increase or decrease? Say why. c) Below are two diagrams showing a microscopic representation of the reaction: X2 + Y AX + XY The diagrams represent the same reaction at two different temperatures: 300 K and 500 K. Is the reaction exothermic or endothermic? Say why. T= 300 K T= 500K Key XY
QUESTION2 For a certain elementary reaction, the rate constant for the forward reaction is 3.6 x 10 "s, and the rate constant for the reverse reaction is 1.2 x 10 3s -1. What is the value of the equilibrium constant? 30 43 23 0.033 QUESTION 3
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QUESTION 19 You add solid Cu3(PO4)2 to a beaker containing 100.0mL of water at 298K. The solid does not appear to dissolve. You wait a long time and eventually measure the equilibrium concentration of PO43- in water to be 5.01x108 M. What is the Ksp of Cuz(PO4)2? Express your answer to the correct number of significant figures and in scientific notation.
Problem 6 10.0 mol PCI, (g), 20.0 mol Cl, (g), and 40.0 mol PCI,(g) are introduced in a previously evacuated 10.0-L vessel at 25.0°C. The K, for the reaction at this temperature is 1.47x10-7: PCI,(9) 2 PCI,(g9) + Cl,(9), = 1.47x10-7 What is the immediate Gibbs free energy change for the reaction? In what direction the reaction will spontaneously approach equilibrium? Enter your answer in the box provided with correct units and sig. figs., and check the correct box below (checking an incorrect box brings negative points): Gibbs free energy Answer: ): AGrxn of the reaction is Reaction proceeds spontaneously forward towards Reaction proceeds spontar sly backward towards Reaction is at equilibrium equilibrium equilibrium
QUESTION 16 At a certain temperature, Kp for the reaction, Br2(g) =2 Br(g) is 0.000229. Calculate the value of Ko for the reaction, 2 Brtg) Br2(g). (Value + 2%)
The reactions below is carried out in a reaction vessel and allowed to reach equilibrium. Which reaction will favor reactant formation upon increasing the volume of the reaction vessel? A) N2 (g) + 3 H2 (g) ↔ 2NH3 (g) B) No right answer C) H2 (g) + F2 (g) ↔ 2 HF(g) D) CO(g) + NO2(g) ↔ CO2(g) + NO(g) E) C(s) + CO2(g) ↔ 2CO(g)