Consider the second step of the three-step ionization of phosphoric acid. The reaction equation would normally be written horizontally as follows: Reactant Arrow H* + Product Select the appropriate reactant, the type of arrow, the product other than H*, and the missing subscript on the equilibrium constant. Note: ^ is used before a superscript Reactant: [ Select ] Arrow: [ Select ] Product: v[ Select ] H2PO4^- PO4^3- Ka [ Sel HPO4^2- НЗРО4
Consider the second step of the three-step ionization of phosphoric acid. The reaction equation would normally be written horizontally as follows: Reactant Arrow H* + Product Select the appropriate reactant, the type of arrow, the product other than H*, and the missing subscript on the equilibrium constant. Note: ^ is used before a superscript Reactant: [ Select ] Arrow: [ Select ] Product: v[ Select ] H2PO4^- PO4^3- Ka [ Sel HPO4^2- НЗРО4
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Correct answer of product and Ka
![Consider the second step of the three-step ionization of phosphoric acid.
The reaction equation would normally be written horizontally as follows:
Reactant Arrow H⁺ + Product
Select the appropriate reactant, the type of arrow, the product other than H⁺, and the missing subscript on the equilibrium constant. Note: ^ is used before a superscript.
- Reactant: [Select]
- Arrow: [Select]
- Product: [Select]
- H₂PO₄⁻
- PO₄³⁻
- HPO₄²⁻
- H₃PO₄
- \(K_a\) [Select]
*This section includes drop-down menus for selecting various options for reactants, arrows, products, and equilibrium constants in the context of the ionization process.*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbde9f375-c451-4db5-93cb-a799e701bdbf%2F8d07ae7c-00d6-4dd2-978b-ab406a2fcbdd%2F3z5equs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the second step of the three-step ionization of phosphoric acid.
The reaction equation would normally be written horizontally as follows:
Reactant Arrow H⁺ + Product
Select the appropriate reactant, the type of arrow, the product other than H⁺, and the missing subscript on the equilibrium constant. Note: ^ is used before a superscript.
- Reactant: [Select]
- Arrow: [Select]
- Product: [Select]
- H₂PO₄⁻
- PO₄³⁻
- HPO₄²⁻
- H₃PO₄
- \(K_a\) [Select]
*This section includes drop-down menus for selecting various options for reactants, arrows, products, and equilibrium constants in the context of the ionization process.*
![**Second Step of the Three-Step Ionization of Phosphoric Acid**
The reaction equation would normally be written horizontally as follows:
\[ \text{Reactant} \ \text{Arrow} \ H^+ \ + \ \text{Product} \]
Select the appropriate reactant, the type of arrow, the product other than \( H^+ \), and the missing subscript on the equilibrium constant. Note: ^ is used before a superscript.
- **Reactant:** [ Select ]
- **Arrow:** [ Select ]
- **Product:** [ Select ]
\[ K_a: \] [ Select ]
Options under \( K_a \):
- 3
- 1
- 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbde9f375-c451-4db5-93cb-a799e701bdbf%2F8d07ae7c-00d6-4dd2-978b-ab406a2fcbdd%2Ficb1rbd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Second Step of the Three-Step Ionization of Phosphoric Acid**
The reaction equation would normally be written horizontally as follows:
\[ \text{Reactant} \ \text{Arrow} \ H^+ \ + \ \text{Product} \]
Select the appropriate reactant, the type of arrow, the product other than \( H^+ \), and the missing subscript on the equilibrium constant. Note: ^ is used before a superscript.
- **Reactant:** [ Select ]
- **Arrow:** [ Select ]
- **Product:** [ Select ]
\[ K_a: \] [ Select ]
Options under \( K_a \):
- 3
- 1
- 2
Expert Solution
Step 1
Phosphoric acid undergo three step ionization because it has three ionizable protons ( H+) . In first step , First H+ is ionized ; in second step , Second H+ and in third step , third H+ is ionized.
So two write the compound involved in Second step , we would first write the chemical equation involved in second step .
Step by step
Solved in 2 steps
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY