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3) A sample vial containing a mixture of phenol, benzene, and bromobenzene was not carefully sealed and left partially open for a couple hours. A GC is taken with only two peaks realized. The first peak to appear has an area of 57 mm² and the second peak 90 mm². What mole% of each compound (specify the compound name) is most likely present?

3) A sample vial containing a mixture of phenol, benzene, and bromobenzene was not carefully sealed and left partially open for a couple hours. A GC is taken with only two peaks realized. The first peak to appear has an area of 57 mm² and the second peak 90 mm². What mole% of each compound (specify the compound name) is most likely present?

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Chromatography Analysis** A sample vial containing a mixture of phenol, benzene, and bromobenzene was not carefully sealed and left partially open for a couple of hours. A gas chromatography (GC) analysis was conducted, yielding only two peaks. The first peak has an area of 57 mm², and the second peak has an area of 90 mm². The task is to determine the mole percentage of each compound likely present in the mixture, specifying the compound names. --- To solve this, one would likely consider the volatility of the compounds, as more volatile substances may have been lost if the vial was left open. This would affect which peaks appeared and their respective areas. Here’s a step-by-step process that can be followed: 1. **Identify Compounds by Volatility:** - Benzene is more volatile than phenol and bromobenzene. - Phenol and bromobenzene remain but might have different volatilities affecting their concentration in the sample. 2. **Analyze Peak Areas:** - Larger peak area corresponds to a higher concentration. - Calculate the total area of peaks: \( 57 \, \text{mm}^2 + 90 \, \text{mm}^2 = 147 \, \text{mm}^2 \). 3. **Calculate Mole Percentages:** - Mole % for the first compound: \(\frac{57}{147} \times 100 \approx 38.78\%\). - Mole % for the second compound: \(\frac{90}{147} \times 100 \approx 61.22\%\). The analysis would suggest which compounds correspond to which peaks, based on the experimental setup and knowledge of the compounds' properties. (Instructor-led explanation or further reading may be required for specific identification). --- This exercise demonstrates the importance of securely sealing samples to prevent changes that can affect analytical results.
Transcribed Image Text:**Chromatography Analysis** A sample vial containing a mixture of phenol, benzene, and bromobenzene was not carefully sealed and left partially open for a couple of hours. A gas chromatography (GC) analysis was conducted, yielding only two peaks. The first peak has an area of 57 mm², and the second peak has an area of 90 mm². The task is to determine the mole percentage of each compound likely present in the mixture, specifying the compound names. --- To solve this, one would likely consider the volatility of the compounds, as more volatile substances may have been lost if the vial was left open. This would affect which peaks appeared and their respective areas. Here’s a step-by-step process that can be followed: 1. **Identify Compounds by Volatility:** - Benzene is more volatile than phenol and bromobenzene. - Phenol and bromobenzene remain but might have different volatilities affecting their concentration in the sample. 2. **Analyze Peak Areas:** - Larger peak area corresponds to a higher concentration. - Calculate the total area of peaks: \( 57 \, \text{mm}^2 + 90 \, \text{mm}^2 = 147 \, \text{mm}^2 \). 3. **Calculate Mole Percentages:** - Mole % for the first compound: \(\frac{57}{147} \times 100 \approx 38.78\%\). - Mole % for the second compound: \(\frac{90}{147} \times 100 \approx 61.22\%\). The analysis would suggest which compounds correspond to which peaks, based on the experimental setup and knowledge of the compounds' properties. (Instructor-led explanation or further reading may be required for specific identification). --- This exercise demonstrates the importance of securely sealing samples to prevent changes that can affect analytical results.
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