OH Determine the type of alcohol the molecule shown here. A) primary B) secondary C) tertiary D) quaternary

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Question 10 of 20

#### Determine the type of alcohol the molecule shown here.

**Diagram:**
The diagram depicts a chemical structure of an alcohol molecule. The molecule consists of a carbon chain where the second carbon atom is attached to a hydroxyl group (-OH). The structure can be described as follows:
- The first carbon is bonded to two hydrogen atoms and one methyl group (-CH3).
- The second carbon, which is attached to the hydroxyl group (-OH), is also bonded to one hydrogen atom and one other carbon atom.
- The third and fourth carbons each are bonded to three hydrogen atoms.

**Options:**
A) primary  
B) secondary  
C) tertiary  
D) quaternary  

**Detailed Description:**
- **Primary alcohols** have the hydroxyl group (-OH) connected to a carbon atom that is attached to only one other carbon.
- **Secondary alcohols** have the hydroxyl group (-OH) attached to a carbon atom that is connected to two other carbon atoms.
- **Tertiary alcohols** have the hydroxyl group (-OH) attached to a carbon atom that is connected to three other carbon atoms.
- **Quaternary alcohols** do not exist, as a quaternary carbon cannot have a hydroxyl group due to having four carbon bonds.

The molecule shown in the diagram has the hydroxyl group (-OH) connected to a secondary carbon atom, which is bonded to two other carbon atoms. Therefore, the molecule is a **secondary alcohol**.

**Correct Answer: B) secondary**
Transcribed Image Text:### Question 10 of 20 #### Determine the type of alcohol the molecule shown here. **Diagram:** The diagram depicts a chemical structure of an alcohol molecule. The molecule consists of a carbon chain where the second carbon atom is attached to a hydroxyl group (-OH). The structure can be described as follows: - The first carbon is bonded to two hydrogen atoms and one methyl group (-CH3). - The second carbon, which is attached to the hydroxyl group (-OH), is also bonded to one hydrogen atom and one other carbon atom. - The third and fourth carbons each are bonded to three hydrogen atoms. **Options:** A) primary B) secondary C) tertiary D) quaternary **Detailed Description:** - **Primary alcohols** have the hydroxyl group (-OH) connected to a carbon atom that is attached to only one other carbon. - **Secondary alcohols** have the hydroxyl group (-OH) attached to a carbon atom that is connected to two other carbon atoms. - **Tertiary alcohols** have the hydroxyl group (-OH) attached to a carbon atom that is connected to three other carbon atoms. - **Quaternary alcohols** do not exist, as a quaternary carbon cannot have a hydroxyl group due to having four carbon bonds. The molecule shown in the diagram has the hydroxyl group (-OH) connected to a secondary carbon atom, which is bonded to two other carbon atoms. Therefore, the molecule is a **secondary alcohol**. **Correct Answer: B) secondary**
### Question 11 of 20
**Compare the following two isomers. Which is more soluble in water? Why?**

#### Diagram of Isomers:
- **Compound 1:** Structural formula is a chain of four carbons (butane) with an -OH (hydroxyl) group attached to the fourth carbon.
- **Compound 2:** Structural formula is a chain of four carbons (butane) with an oxygen atom linking the second and third carbons, forming an ether.

#### Answer Choices:
- **A) Compound 1 is more soluble because it has greater ability to hydrogen bond with water.**
- **B) Compound 2 is more soluble because it has greater ability to hydrogen bond with water.**
- **C) Neither of these compounds are water soluble.**
- **D) Compound 1 is more soluble because it will have more dipole-dipole interactions with water.**
- **E) Compound 2 is more soluble because it will have more dipole-dipole interactions with water.**

### Explanation:
The exercise at hand requires evaluating the solubility of two isomers in water. Both compounds have the same molecular formula but different functional groups, resulting in distinct chemical properties.

**Compound 1** has a hydroxyl group (-OH), which is known for its strong ability to form hydrogen bonds with water molecules. This significantly enhances its solubility in water.

**Compound 2** features an ether functional group (C-O-C). While ethers do interact with water through dipole-dipole interactions, they are generally less effective at forming hydrogen bonds compared to hydroxyl groups.

Considering the capacity of hydrogen bonding as a significant factor in determining water solubility, **Compound 1** is expected to be more soluble in water than **Compound 2**. 

### Conclusion:
The correct answer is:
- **A) Compound 1 is more soluble because it has greater ability to hydrogen bond with water.**
Transcribed Image Text:### Question 11 of 20 **Compare the following two isomers. Which is more soluble in water? Why?** #### Diagram of Isomers: - **Compound 1:** Structural formula is a chain of four carbons (butane) with an -OH (hydroxyl) group attached to the fourth carbon. - **Compound 2:** Structural formula is a chain of four carbons (butane) with an oxygen atom linking the second and third carbons, forming an ether. #### Answer Choices: - **A) Compound 1 is more soluble because it has greater ability to hydrogen bond with water.** - **B) Compound 2 is more soluble because it has greater ability to hydrogen bond with water.** - **C) Neither of these compounds are water soluble.** - **D) Compound 1 is more soluble because it will have more dipole-dipole interactions with water.** - **E) Compound 2 is more soluble because it will have more dipole-dipole interactions with water.** ### Explanation: The exercise at hand requires evaluating the solubility of two isomers in water. Both compounds have the same molecular formula but different functional groups, resulting in distinct chemical properties. **Compound 1** has a hydroxyl group (-OH), which is known for its strong ability to form hydrogen bonds with water molecules. This significantly enhances its solubility in water. **Compound 2** features an ether functional group (C-O-C). While ethers do interact with water through dipole-dipole interactions, they are generally less effective at forming hydrogen bonds compared to hydroxyl groups. Considering the capacity of hydrogen bonding as a significant factor in determining water solubility, **Compound 1** is expected to be more soluble in water than **Compound 2**. ### Conclusion: The correct answer is: - **A) Compound 1 is more soluble because it has greater ability to hydrogen bond with water.**
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