Problem # 4 Determine the structure of the compound with the spectra provided and molecular formula C9H1003. 3500 180 160 1H (exchanges) ये 3000 40 ठे 2H triplet 120 1H triplet 2-2545 -2637 941 2000 1500 2500 100 80 2H doublet ठे 1718 2H triplet 1433 2H triplet रे 1000 13 ठे

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Problem #4 Determine the structure of the compound with the spectra provided and molecular
formula C9H1003.
3500
T80
160
1H (exchanges)
1
Tb
3000
140
-2637
2-2545
2500
100
Way
1H
triplet
2H
doublet
+
2H
triplet
2000
1718
2H
triplet
1433
1500
2H
triplet
1000
Transcribed Image Text:Problem #4 Determine the structure of the compound with the spectra provided and molecular formula C9H1003. 3500 T80 160 1H (exchanges) 1 Tb 3000 140 -2637 2-2545 2500 100 Way 1H triplet 2H doublet + 2H triplet 2000 1718 2H triplet 1433 1500 2H triplet 1000
Expert Solution
Step 1: Introduce the problem

Data from the given spectra:

Molecular formula: C9H10O3

IR Spectra:

Broad band from 2500-3050 cm-1

Strong absorption at 1718 cm-1

Finger print region absorption at 1433cm-1 and 1235 cm-1

13C NMR  Spectra:

7 13C  signals around ~ 176ppm, 158ppm, 130ppm, 120ppm, 115ppm, 64ppm and 35ppm

1H NMR  Spectra:

1 H exchanges around 12ppm

2 H triplet ~7.3ppm

1 H triplet ~6.95ppm

2 H doublet ~6.90ppm

2 H triplet ~4.2ppm

2 H triplet ~2.7ppm






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