Problem 4 Determine: • The impedance, ZÃ, of load A. Load A accepts complex power SA The total complex power delivered by the source The total power factor of the circuit 24V/10° A SA 11.5/36.9°,VA B ZB = 30 + j30

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I turned the voltage value of the AC source into Vrms and got magnitude 16.97 & angle 10.
Then calculated the impedance of Load A to be [ -9.28 - j23.4 ].
From that, I calculated the complex power of load B to be [ -2.42 + j6.33 ]
my power factor calculation I am using inverse tan ( Q/P) , where Q i got -1.91 & P to be 5.559, which I got from my total complex power. If that helps.

But I am calculating a negative power factor, so i am curious where I went wrong, Thank you!

Problem 4
Determine:
The impedance, ZÃ, of load A. Load A accepts complex power SA
• The total complex power delivered by the source
• The total power factor of the circuit
24V/10°
A
S = 11.5/36.9°, VA
B
ZB = 30+j30
Transcribed Image Text:Problem 4 Determine: The impedance, ZÃ, of load A. Load A accepts complex power SA • The total complex power delivered by the source • The total power factor of the circuit 24V/10° A S = 11.5/36.9°, VA B ZB = 30+j30
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