What I think I have so far and starting with negation is "there exist some n so that n and n+9 are both even" to find a contradiction which is 2n=n+9 => n=9 so n will never be even. Not sure if this is write or how if the explanation is correct Problem 3.3. Prove by contradiction that there exists no n e Z such that both n andn +9 are even.Hint. How to interpret the negation of "there exists no n e Z such that both n and n+ 9are even"? Assume the negation and try to reach a contradiction.

Problem 3.3. Prove by contradiction that there exists no n e Z such that both n and n +9 are even. Hint. How to interpret the negation of "there exists no n e Z such that both n and n+ 9 are even"? Assume the negation and try to reach a contradiction.

Problem 3.3. Prove by contradiction that there exists no n e Z such that both n and n +9 are even. Hint. How to interpret the negation of "there exists no n e Z such that both n and n+ 9 are even"? Assume the negation and try to reach a contradiction.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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kindly answer it perfectly
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