**Problem 3.24 (page 119):** The soil in a watershed has the following properties: - θ₀ = 0.02- θₚ = 0.25- θₛₐₜ = 0.38The watershed has a composite ARC II curve number of CN₁₁ = 80. A storm with a rainfall of 30 mm occurs in the dormant season. During the five days before the storm begins, the total rainfall is 25 mm. Estimate the direct runoff from this storm using the MoRE and SCS-CN models.

Answered: Image /qna-images/answer/22e514b9-036b-4740-abd4-32a3c5a3ae8a.jpg

Answered: Problem 3.24 (page 119): The soil in a…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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X (d) What is the probability that a 5-vear flood will occur three times in a period of 10 years? What is the probability that it will occur at all? How many floods of this magnitude will occur, on average, during the 10 years?
please show steps
Subject: ( Hydrology and water Resources management )
6. Show the 50-year, constant-intensity design storm for a watershed in Baltimore with a time of concentration of 30 minutes. Also show the 10-year, 15-min, constant-intensity design storm for a watershed in Baltimore. Baltimore, Maryland 1903-1951 20.0 15.0 Note Frequency analysis by method of extreme value after gumbel 10.0 80 6.0 Return period (years) 4.0 100 so 2.0 2 0.8 0.6 0.4 0.2 0.1 0.08 0.06 0.04 0.02 10 15 20 30 40 S060 3 456 8 1012 18 24 Minutes Hours Duration Rainfall intensity (in./hr)
Hydrology problem, please solve it
C. Isohyetal Method?
Net Storm Rainfall Example 2-1 Rain falls as shown in the rainfall hyetograph (intensity Vs. time) in Fig. E2-1 (a). The o index for the Storm is 0.5 in./hr and is constant over 5 hr. Plot the net rainfall on the hydrograph (flow vs. time) given in Fig. E2-1 (a). Determine the total volume of runoff and the watershed area. 1cfs = 1.008 ac-in/hr 2.0 1.5 1.0 0.5 1 3. 4 Time (hr) 700 600 500 400 300 200 100 4 8 12 16 20 24 Time (hr) Time (hr) Q (cfs) Volume (cfs-hr) 0-2 2-4 4-6 6-8 8-10 10-12 12-14 14-16 16-18 18-20 20-22 22-24 24-26 16 Q (cfs) iT (in./hr)
Rational Method: Determine the pre (C = 0.3) and post development (C= 0.75) peak runoff for a 90-acre site that experiences a 0.35 inches/hour rainfall intensity, using the rational method. Show all your work, including any assumptions you will make.
The ordinates of a 6h-UH of a watershed having a drainage area of 393 km^2 are given below. For a storm over the watershed having excess rainfall of 5 cm for the first six hours and 15 cm for the second six hours, compute the direct runoff hydrograph ordinates and plot the hydrograph. Compute the depth of direct runoff in cm. Assuming constant baseflow of 100 m^3/s, compute the storm hydrograph ordinates and plot the hydrograph. (List all the DRH ordinates in order, separated by a single space.)
A 300 acre watershed just south of Chicago is currently undeveloped (woods). The soils are primarily clay, the hydraulic length of the watershed is 6560 ft, and the average lank slope is 1%. Determine the SCS synthetic UH before development and finish the table below. Solution: from Table 11.7; 1. For clay soil with woods cover, CN= 2. The soil moisture deficit S = in; 3. For a watershed with hydraulic length, time of concentration Te= hr min; 4. Time to peak Tp= min: 5. Peak discharge Op= cfsjin; 6. Storm duration is AD= hr= min; 7. The -min UH is displayed below using Table 11.11; Flow Time Time Ratios Flow Ratios (min) (cfs) (t/tp) (9/ap) 21 13 0.1 0.2 40 42 0.31 0.4 0.66 0.6 0,93 0.8 125 121 0.93 1.2 102 146 1.4 0.78 167 73 0.56 1.6 51 188 0.39 1.8
Subject water resource
Calculate the runoff from a watershed of (0.01 x 4737) ha. The following data are available: Depth of rainfall is 100 mm. Antecedent rainfall condition, AMC 1: Row crop, good condition in 40 ha (Soil group C) Woodland, good condition in 20 ha (Soil group B) The day after the rainfall of 100 mm, another rainfall of 50 mm occurred. Solve for the surface runoff from the watershed. [ NOTE: Where R is the last four digits of your Registration Number. R = 4737 ]

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