Problem 3. Let pEP2. Consider the interpolation problem with the following degrees of freedom: p(0) = Po, p'(1) = P₁, and f₁ p(x) dx = (p). 1. Write the Vandermonde matrix for this interpolation problem. 2. Write down the coefficients of the cardinal basis for this interpolation problem in the monomial basis. 3. Graph the cardinal basis functions. 4. "Taking the average of a polynomial is the same as computing a dot product with its monomial basis coefficient vector." Explain what this means. 5. Let po = 0, p₁ = 1, and (p) = µ. Let pμ(x) be the solution of the interpolation problem with this data. Graph pu from x = 0 to x = 1 for μ = 0, 1, 2.

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Problem 3. Let p = P². Consider the interpolation problem with the following degrees of freedom:
p(0) = po, p′(1) = p₁, and ſ₁ p(x)dx = (p).
1. Write the Vandermonde matrix for this interpolation problem.
2. Write down the coefficients of the cardinal basis for this interpolation problem in the monomial basis.
3. Graph the cardinal basis functions.
4. "Taking the average of a polynomial is the same as computing a dot product with its monomial basis
coefficient vector." Explain what this means.
5. Let po = 0, p₁ = 1, and (p) = µ. Let pμ(x) be the solution of the interpolation problem with this data.
Graph pu from x = 0 to x = 1 for µ = 0, 1, 2.
Transcribed Image Text:Problem 3. Let p = P². Consider the interpolation problem with the following degrees of freedom: p(0) = po, p′(1) = p₁, and ſ₁ p(x)dx = (p). 1. Write the Vandermonde matrix for this interpolation problem. 2. Write down the coefficients of the cardinal basis for this interpolation problem in the monomial basis. 3. Graph the cardinal basis functions. 4. "Taking the average of a polynomial is the same as computing a dot product with its monomial basis coefficient vector." Explain what this means. 5. Let po = 0, p₁ = 1, and (p) = µ. Let pμ(x) be the solution of the interpolation problem with this data. Graph pu from x = 0 to x = 1 for µ = 0, 1, 2.
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