Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg-m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 m. 4 = 0.3962 / Correct! Part (b) Now calculate the moment of inertia of the skater (in kg m-) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends. I= 2.3 sin() cos() tan() 8 HOME cotan() asin() acos() E 4 6 atan() acotan() sinh() 1|23 * cosh() ODegrees O Radians tanh() cotanh() + END VOl BACKSPACE CLEAR DEL Submit I give up! Hint Feedback
Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg-m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 m. 4 = 0.3962 / Correct! Part (b) Now calculate the moment of inertia of the skater (in kg m-) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends. I= 2.3 sin() cos() tan() 8 HOME cotan() asin() acos() E 4 6 atan() acotan() sinh() 1|23 * cosh() ODegrees O Radians tanh() cotanh() + END VOl BACKSPACE CLEAR DEL Submit I give up! Hint Feedback
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![Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass.
Part (a) First calculate the moment of inertia (in kg-m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11
m.
4 = 0.3962
/ Correct!
Part (b) Now calculate the moment of inertia of the skater (in kg m-) with their arms extended by assuming that each arm is 5% of the mass of
their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being
rotated at the ends.
I= 2.3
sin()
cos()
tan()
7
8
HOME
cotan()
asin()
acos()
4
5
6
atan()
acotan()
sinh()
1|23
cosh()
tanh()
cotanh()
+
-
END
ODegrees O Radians
vol BACKSPACE
DEL
CLEAR
Submit
I give up!
Hint
Feedback](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8bdf8f1e-a074-4944-9e95-7b5187bdd920%2Fb4eef73b-b130-4447-999a-90c8be59271a%2F5vhdv1n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass.
Part (a) First calculate the moment of inertia (in kg-m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11
m.
4 = 0.3962
/ Correct!
Part (b) Now calculate the moment of inertia of the skater (in kg m-) with their arms extended by assuming that each arm is 5% of the mass of
their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being
rotated at the ends.
I= 2.3
sin()
cos()
tan()
7
8
HOME
cotan()
asin()
acos()
4
5
6
atan()
acotan()
sinh()
1|23
cosh()
tanh()
cotanh()
+
-
END
ODegrees O Radians
vol BACKSPACE
DEL
CLEAR
Submit
I give up!
Hint
Feedback
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