Problem 3 Suppose that a Bayesian spam filter is trained on a set of 500 spam messages and 200 messages that are not spam. The word "exciting" appears in 40 spam messages and in 25 messages that are not spam. Would an incoming message be rejected as spam if it contains the word "exciting" and the threshold for rejecting spam is 0.9?

Q: w + 4 w + 10 6. 8.

A:

Q: 4s +5 S -4

A:

Q: 2/7 + -4/3

A: Given,

Q: x +y = - 12 2x - 3y = 6

A: Solved below

Q: 3y² - 2y-1 (-)-5y²- 2y +6

A:

Q: From the list below, select the values of x for which f'(x) > 0. 2 -1 None of the listed x values -3…

A: Given graph of function

Q: 5 3 4 x-3 x-2 x-3'

A: Given that 5/(x-3)-3/(x-2)=4/(x-3) To solve for x

Q: 2 +,

A:

Q: n is the same as 239 added to the product of 238 and z

A:

Q: V81x6 V3x3

A: Given expression is:  81x63x3 =81x63x3=27x6-3

Q: S₁ y² – 3ydy 11

A:

Q: Consider F(x) = = F(0) = 0 F'(3) = 6 F'(1) = 0 O F'(4) = 10 F'(2) = 2 I tf(t) tf(t) dt. Which of the…

A:

Q: y X (9, –3)

A:

Q: f(-0.5) =

A: We have to find f(-0.5)

Q: 5 3 + s2-8 s2+ 3.

A:

Q: 目 +8 LI +T 现 +04 +C4 |F|E|F|| ||||4 4 4 2 2

A:

Q: Find A.

A:

Q: -2(5a)

A: To evaluate-2(5a)

Q: Find A. -6 4 (4A)-1 -2 1 A =

A:

Q: 2. -ў — 2у %3D 6

A: answer is in next step

Q: (24) Half the product of a number t and 48

A: The objective is to half the product of a number t and 48.

Q: 10. 3 + Зу- 1 + у

A: Given that                     3+3y-1+y Now we simplify this.                           3+3y-1+y…

Q: X5 y / x4 y6

A: Given: x5yx4y6

Q: 2/21 + -2/9.

A: 221+−29

Q: w+5 -dw w - 6w+10

A: A detailed solution is given below

Q: find -1 2 5+1 s(5+1)²

A:

Q: 4 5x2 Evaluate dx. TV3x2-1

A:

Q: Multiply.     (x+y ) 2

A: The given expression x+y2.

Q: –4(–6m – 7).

A:

Q: Find the interpolating polynomial of the following points or functions using Newton's interpolation…

A: Newton's divided differences interpolation

Q: -3 -2 -1 1 2 0000000 3.

A:

Q: (9, -7) (3, 1). Find 吕 ロ师仁 ?

A:

Q: -4 -2- 4 8

A: We are asked to find the horizontal asymptote and vertical asymptote. Horizontal asymptote (HA) - It…

Q: y +y - 2y = 0

A: Here we have to solve , the given differential equation  y"+y'-2y=0 ...........(1)

Q: 2x - 1 5. Find Lt x + 1 X-2 8个x

A: Introduction :

Q: 2. (1 + 3/2x − 1)² = 3 + √3/2x − 1

A:

Q: b. V3x -11= x+1 ,2

A: Solving on graph

Q: -7 -5 Let A = Find -2A. 2] 1.

A: Given, A=-7-512