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2. (1 + 3/2x − 1)² = 3 + √3/2x − 1

2. (1 + 3/2x − 1)² = 3 + √3/2x − 1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solving Equations involving Radicals The equation obtained by raising both sides of an equation may have a solution that is not a solution of the original equation. To solve equations involving radicals: 1. Raise both sides of the equations to the appropriate power. 2. Solve the equation that arises. 3. Check for extraneous solutions. Note: In solving equations, we check for extraneous solutions whenever we raise both sides of an equation to a power. Theorem Let A and B be expressions and let n € N. The solution set of the equation A = B is a subset of the solution set of A" = B".
Transcribed Image Text:Solving Equations involving Radicals The equation obtained by raising both sides of an equation may have a solution that is not a solution of the original equation. To solve equations involving radicals: 1. Raise both sides of the equations to the appropriate power. 2. Solve the equation that arises. 3. Check for extraneous solutions. Note: In solving equations, we check for extraneous solutions whenever we raise both sides of an equation to a power. Theorem Let A and B be expressions and let n € N. The solution set of the equation A = B is a subset of the solution set of A" = B".
2 3 2. (1+ 2x − 1)² = 3 = 3 + 2x - 1
Transcribed Image Text:2 3 2. (1+ 2x − 1)² = 3 = 3 + 2x - 1
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