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Problem 3: Inputs: ● ● F = 1800 N P = 600 N (same as previous problem) a = b = 3 m (same as previous problem) c = 8 m (same as previous problem) The frame is comprised of two members. All joints are pinned. Compute the reactions at pins A and C, as well as the forces at pin B. a) Ax (Indicate left/right) b) Ay (Indicate up/down) c) Cx (Indicate left/right) d) Cy (Indicate up/down) P A a B b

Problem 3: Inputs: ● ● F = 1800 N P = 600 N (same as previous problem) a = b = 3 m (same as previous problem) c = 8 m (same as previous problem) The frame is comprised of two members. All joints are pinned. Compute the reactions at pins A and C, as well as the forces at pin B. a) Ax (Indicate left/right) b) Ay (Indicate up/down) c) Cx (Indicate left/right) d) Cy (Indicate up/down) P A a B b

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Problem 3: Inputs: ● F = 1800 N P = 600 N (same as previous problem) a = b = 3 m (same as previous problem) c = 8 m (same as previous problem) The frame is comprised of two members. All joints are pinned. Compute the reactions at pins A and C, as well as the forces at pin B. P с a) Ax (Indicate left/right) b) Ay (Indicate up/down) c) Cx (Indicate left/right) d) Cy (Indicate up/down) e) Bx (no need to indicate direction since this is an internal force) f) a F B b C Net force in y-direction at pin B, using the FBD for bar BC. This is not necessarily By by itself. Again, no need for direction here.
Transcribed Image Text:Problem 3: Inputs: ● F = 1800 N P = 600 N (same as previous problem) a = b = 3 m (same as previous problem) c = 8 m (same as previous problem) The frame is comprised of two members. All joints are pinned. Compute the reactions at pins A and C, as well as the forces at pin B. P с a) Ax (Indicate left/right) b) Ay (Indicate up/down) c) Cx (Indicate left/right) d) Cy (Indicate up/down) e) Bx (no need to indicate direction since this is an internal force) f) a F B b C Net force in y-direction at pin B, using the FBD for bar BC. This is not necessarily By by itself. Again, no need for direction here.
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