Problem 3: In the Figure below three ropes are used to drag a box a distance d = 3 m across the floor. There is no friction between the box and the ground. a) How much work is done by the tension force T₁? Answer: 1691.4 J b) How much work is done by the tension force T₂? Answer: 1065.2 J c) How much work is done by the tension force T3? Answer: -1980 J 660 N T₂ T₂ T₁ 600 N 20° 30° 410 N
Problem 3: In the Figure below three ropes are used to drag a box a distance d = 3 m across the floor. There is no friction between the box and the ground. a) How much work is done by the tension force T₁? Answer: 1691.4 J b) How much work is done by the tension force T₂? Answer: 1065.2 J c) How much work is done by the tension force T3? Answer: -1980 J 660 N T₂ T₂ T₁ 600 N 20° 30° 410 N
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Problem 3:
In the Figure below three ropes are used to drag a box a distance d = 3 m across the floor.
There is no friction between the box and the ground.
a) How much work is done by the tension force T₁? Answer: 1691.4 J
b) How much work is done by the tension force T₂? Answer: 1065.2 J
c) How much work is done by the tension force T3? Answer: -1980 J
660 N T₂
T₂
T₁
600 N
20°
30°
410 N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcdbdf4c8-5459-45de-99f8-cd8d71031beb%2F9cad41ba-7042-466d-ad17-d05f8859a176%2Fwu2pqyt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 3:
In the Figure below three ropes are used to drag a box a distance d = 3 m across the floor.
There is no friction between the box and the ground.
a) How much work is done by the tension force T₁? Answer: 1691.4 J
b) How much work is done by the tension force T₂? Answer: 1065.2 J
c) How much work is done by the tension force T3? Answer: -1980 J
660 N T₂
T₂
T₁
600 N
20°
30°
410 N
![W = F₁Ax = F· Ax, Wnet = m(v₁) ² - ² m(v₁)², W = F₂dx, W = F·dr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcdbdf4c8-5459-45de-99f8-cd8d71031beb%2F9cad41ba-7042-466d-ad17-d05f8859a176%2F87bwmxn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:W = F₁Ax = F· Ax, Wnet = m(v₁) ² - ² m(v₁)², W = F₂dx, W = F·dr
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