Problem 3: For what emf & does the 2002 resistor in Fig.3 dis- sipate no power? Should the emf be oriented with its positive terminal at the top or at the bottom? a) If the 200 S2 resistor dissipates no power, what does this mean for the distribution of the currents in the circuit? In other words, how are the currents through the different resistors related in this case? SOV 10052 ww 20052 30052 ww £? FIG. 3: The scheme for Problem 3

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Hello, I really need help with part A and Part B, I was just wondering if you can help me with PART A and Part B and can you also label them as well.

**Problem 3:** 

For what emf \( \mathcal{E} \) does the 200 \(\Omega\) resistor in Fig. 3 dissipate no power? Should the emf be oriented with its positive terminal at the top or at the bottom?

a) If the 200 \(\Omega\) resistor dissipates no power, what does this mean for the distribution of the currents in the circuit? In other words, how are the currents through the different resistors related in this case?

b) Choose any two different closed loops in the circuit and write down Kirchhoff’s loop law for these loops. It must be possible to solve these two equations for the current and the emf \( \mathcal{E} \).

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**Diagram Description:**

- The diagram labeled "FIG. 3: The scheme for Problem 3" shows an electrical circuit.
- The circuit includes:
  - A 50V battery with positive on the top and negative on the bottom.
  - A 100 \(\Omega\) resistor and a 300 \(\Omega\) resistor in series with each other.
  - A 200 \(\Omega\) resistor connected in parallel to the 300 \(\Omega\) resistor.
  - An unknown emf \( \mathcal{E} \) is connected to this arrangement, in parallel with the 200 \(\Omega\) resistor.

To solve this problem, one will need to apply electrical principles such as Kirchhoff’s laws and analyze the circuit configuration to determine how the emf should be oriented and what its value should be for no power dissipation through the 200 \(\Omega\) resistor.
Transcribed Image Text:**Problem 3:** For what emf \( \mathcal{E} \) does the 200 \(\Omega\) resistor in Fig. 3 dissipate no power? Should the emf be oriented with its positive terminal at the top or at the bottom? a) If the 200 \(\Omega\) resistor dissipates no power, what does this mean for the distribution of the currents in the circuit? In other words, how are the currents through the different resistors related in this case? b) Choose any two different closed loops in the circuit and write down Kirchhoff’s loop law for these loops. It must be possible to solve these two equations for the current and the emf \( \mathcal{E} \). --- **Diagram Description:** - The diagram labeled "FIG. 3: The scheme for Problem 3" shows an electrical circuit. - The circuit includes: - A 50V battery with positive on the top and negative on the bottom. - A 100 \(\Omega\) resistor and a 300 \(\Omega\) resistor in series with each other. - A 200 \(\Omega\) resistor connected in parallel to the 300 \(\Omega\) resistor. - An unknown emf \( \mathcal{E} \) is connected to this arrangement, in parallel with the 200 \(\Omega\) resistor. To solve this problem, one will need to apply electrical principles such as Kirchhoff’s laws and analyze the circuit configuration to determine how the emf should be oriented and what its value should be for no power dissipation through the 200 \(\Omega\) resistor.
Expert Solution
Step 1 unknown emf

It is given that no power dissipates along the 200 Ω resistor.

It means there should be no current across the 200 Ω resistor. So we have to choose the emf value and its orientation in such a way that the potential across the ends of the 200 Ω resistor becomes the same.

 

According to Kirchhoff's current law, the sum of all incoming current at a branch point is equal to the sum of all outgoing currents.

Iincoming=Ioutgoing

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