Problem 3: A soil sample has a liquid limit of 70 % and plastic limit of 50 %.U-line : PI = 0.9 (LL - 8)A- Line: PI = 0.73 (LL - 20)601. Determine the point of intersection of the U-line and A-line.2. Compute the shrinkage limit, SL using the plasticity chart.3. Compute the Specific Gravity, Gs of the Soil if SR = 1.37.ALine PI -07NL - 20)2010406000Liguid limiPlasticity indes

Liquid limit:- Liquid limit is the water content where the soil starts to behave as a liquid. Platic…

Answered: Problem 3: A soil sample has a liquid…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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U B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D₁0 = 70 μm L.L = 36% P.L = 31% D8 = 2 µm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%.
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Q': A- Classification tests have been performed on a soil sample and the grading curve that shown in (Fig. 1) and Atterberg limits obtained. Classify the soil using the USCS? L.L=32 and P.L=26 100 80 60 40 20 Fig. 1 0.1 1 Particle size (mm) 0.0001 0.001 0.01 10 100 % Finer
A soil specimen has a total volume of 70 cm3 and a total mass of 135.5g. After complete drying in an oven, the specimen has a mass of 122.0g. The Gs is 2.60. Determine the void ratio. Report your answer to three significant figures, and draw the full phase diagram.
During Atterberg limit tessts in the Naboratory,the studens obtained the following results froma clayey soil. Wumber of Blows (N) Molsture Content \ 38/4 16 36/5 20 33.1 28 2/7 0 Plastic limit tests: Students conducted two trials and found that PL= 17 2% for the first trial and PL = 18.4% for the second trial. Assume that the liquid limit of the soil iS LL= 29.0% a. Determine the flow index. b. Determine the liquidity index of the soil if the in situ moisture content is 22.0%.
Q2) Classify a soil using USCS from the following information: 75% of the material is retained on the sieve No.200. less than of the percent above and more than 50%, is passing on the sieve No.4. L.L. 35% and P.L.= 29% D10 0.18mm, D30 = 0.88mm, and D60 = 1.12mm d)
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3-8 A 1-ft3 of undisturbed soil sample has a dry weight of 107 lbs. The specific gravity of the soil solids is 2.70. Need Vs VT = 1 To solve for Vs = use the following equation Ws=Vs*Gs*yw (solve for Vs) a) Calculate the void ratio of the sample. b) Calculate the porosity of the sample. DC
A 59m3 soil sample having a degree of saturation of 96% at the liquid limit of 29%. At the plastic limit of the soil has a volume of 42m3. This soil sample was subjected to sieve analysis in the attached photo below. Find: a.Void ratio at Plastic limit b.Plastic limit c.Modified percentage of sand, silt and clay d.Classification of soil according to USDA
1. A dry sand is placed in a container having a volume of 0.0092 cubic centimeter. The dry unit weightof the sample is 0.015 gram. Water is carefully added to the container so as not to disturbed thecondition of the sand. When the container is filled, the combined weight of soil plus water is 0.0182gram.a. Determine the specific gravity of soil particle.b. Determine the dry unit weight of soil.2. If the soil sample has a water content of 11% and a unit weight of 19.67 kN/m3 , determine thepercentage of air in voids and the degree of saturation if the specific gravity of soil solid is 2.75.3. If the soil sample has a specific gravity of 2.71 and a porosity of 0.345, determine the saturated unitweight and the bouyant unit weight.4. A soil sample having a liquidity index of 0.85, a plasticity index of 16.50 and a plastic limit of 11.45.The soil sample has a specicfic gravity of 2.68 and a void ratio of 0.77.a. Compute the degree of saturation.b. Compute the air void ratio.

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