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Problem-3: A coaxial cable consists of two long tubes, separated by linear insulating material of mag- netic susceptibility Xm· A current / flows down the inner conductor and returns along the outer one. We need to determine the magnetic field, B, in the regions r > b and a < r< b by two methods: - First Method: (a) Determine the auxiliary field, Ĥ =?, in the regions r > b and a b and a < r < b. - Second Method: (e) Determine the magnetization, M =?, in the regions r > b and a b and a

Problem-3: A coaxial cable consists of two long tubes, separated by linear insulating material of mag- netic susceptibility Xm· A current / flows down the inner conductor and returns along the outer one. We need to determine the magnetic field, B, in the regions r > b and a < r< b by two methods: - First Method: (a) Determine the auxiliary field, Ĥ =?, in the regions r > b and a b and a < r < b. - Second Method: (e) Determine the magnetization, M =?, in the regions r > b and a b and a

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Problem-3: A coaxial cable consists of two long tubes, separated by linear insulating material of mag- netic susceptibility Xm· A current I flows down the inner conductor and returns along the outer one. We need to determine the magnetic field, B, in the regions r > b and a <r < b by two methods: - First Method: (a) Determine the auxiliary field, Ĥ =?, in the regions r > b and a <r < b. (b) Deduce the magnetic field, B =?, in the regions r > b and a <r< b. - Second Method: (e) Determine the magnetization, M =?, in the regions r > b and a < r < b. (f) Deduce the bound currents, b =? and Kp =?, in the region a <r<b. (g) Apply Ampere's law to determine the magnetic field, B =?, in the regions r > b and a <r < b.
Transcribed Image Text:Problem-3: A coaxial cable consists of two long tubes, separated by linear insulating material of mag- netic susceptibility Xm· A current I flows down the inner conductor and returns along the outer one. We need to determine the magnetic field, B, in the regions r > b and a <r < b by two methods: - First Method: (a) Determine the auxiliary field, Ĥ =?, in the regions r > b and a <r < b. (b) Deduce the magnetic field, B =?, in the regions r > b and a <r< b. - Second Method: (e) Determine the magnetization, M =?, in the regions r > b and a < r < b. (f) Deduce the bound currents, b =? and Kp =?, in the region a <r<b. (g) Apply Ampere's law to determine the magnetic field, B =?, in the regions r > b and a <r < b.
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