Problem 3: A baseball of mass m = 0.37 kg is spun vertically on a massless string of length L= 0.55 m. The string can only support a tension of Tmax = 11 N before it will break. Randomized Variables m = 0.37 kg L = 0.55 m Tmax = 11 N Part (a) What is the maximum possible speed of the ball at the top of the loop, in meters per second? Vt, max = sin() cos() tan() 8 9 HOME cotan() asin() acos() 4 6 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END O Degrees O Radians VO BACKSPACE DEL CLEAR
Problem 3: A baseball of mass m = 0.37 kg is spun vertically on a massless string of length L= 0.55 m. The string can only support a tension of Tmax = 11 N before it will break. Randomized Variables m = 0.37 kg L = 0.55 m Tmax = 11 N Part (a) What is the maximum possible speed of the ball at the top of the loop, in meters per second? Vt, max = sin() cos() tan() 8 9 HOME cotan() asin() acos() 4 6 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END O Degrees O Radians VO BACKSPACE DEL CLEAR
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please answer all the parts

Transcribed Image Text:Problem 3: A baseball of mass m = 0.37 kg is spun vertically on a massless string of length
L = 0.55 m. The string can only support a tension of Tmax = 11 N before it will break.
Randomized Variables
m = 0.37 kg
L = 0.55 m
Tmax = 11 N
Part (a) What is the maximum possible speed of the ball at the top of the loop, in meters per second?
Vt,max =
sin()
cos()
tan()
7
8
9
JT
НОМE
cotan()
asin()
acos()
E
4
atan()
acotan()
sinh()
3
cosh()
tanh()
cotanh()
+
END
O Degrees O Radians
VO BACKSPACE
DEL CLEAR

Transcribed Image Text:Part (b) What is the maximum possible speed of the ball at the bottom of the loop, in meters per second?
Vb,max =
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