Problem 36 bits000000You are given the following machine instruction (the number of bits per field is shown too).5 bits5 bits5 bits0010000011000005 bits000016 bits011001What is the instruction in assembly language? Choose one of the following:(a) add $1, $2, $3(b) sub $3, $1, $4(c) or $4, $3, $1(d) sit $1, $3, $4(e) None of the above.

Answer: We have explain each and every point related to given information in brief explanation.

Problem 3 6 bits 000000 You are given the following machine instruction (the number of bits per field is shown too). 5 bits 5 bits 6 bits 00001 00100 011001 5 bits 00011 5 bits 00000 What is the instruction in assembly language? Choose one of the following: (a) add $1, $2, $3 (b) sub $3, $1, $4 (c) or $4, $3, $1 (d) sit $1, $3, $4 (e) None of the above.

Problem 3 6 bits 000000 You are given the following machine instruction (the number of bits per field is shown too). 5 bits 5 bits 6 bits 00001 00100 011001 5 bits 00011 5 bits 00000 What is the instruction in assembly language? Choose one of the following: (a) add $1, $2, $3 (b) sub $3, $1, $4 (c) or $4, $3, $1 (d) sit $1, $3, $4 (e) None of the above.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Write the machine code of the instruction: subwf Ox53, 1 How to write answer: Write 4-digits hexadecimal value starting without '0x'. Example: if answer is 0X245F, then write 245F Example: if answer is 0X005F, then write 005F Answer:
This is Computer Architecture! Instructions: Create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. The program’s output should look something like the following where the xxx’s are the numbers you chose. The resulting numbers may be different than mine depending on your choice of a, b, and c. Using a = xxx, b = xxx, and c = xxx a + (b + c) = 0 (a + b) + c = 1 The key is to have two of the number large (one positively and one negatively but equal in magnitude) floating point numbers and the third floating point number very small in comparison. Please don't forget to include comments in this code
This is Computer Architecture! Instructions: Create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. The key is to have two of the number large (one positively and one negatively but equal in magnitude) floating point numbers and the third floating point number very small in comparison. ***Please don't forget to include comments in this code, and also include a screenshot of the program working!***
For example, instruction like this. 0011 0000 0000 0000 ; start at x30000001 001 001 1 00000 ;x3000 set N CC if R1 < 00000 100 0 0000 0001 ;x3001 if N goto x3003 R2+=50000 111 0 0000 0001 ;x3002 Not N goto x30040001 010 010 1 00101 ;x3003 R2 += 5;x3004 done
Computer Science Implement the following expression in assembly language: EAX = (valDW1+valDW2) −EBX. Assume that valDW1 and valDW2 are 32-bit integer variables.
Memory 12200 12201 12202 12203 12204 Content %D AA EE FF 22 What result is produced in the destination operand by execution the following instruction? a- LEA SI[DI+Bx+5] b- LDS SI.[200]
Q7. are 0, 0, 1, and 0, respectively. Find the value of the N, Z, C, V flags of the following instructions (assume each instruction runs individually, i.e., these instructions are not part of a program). Suppose r0 = 0XFFFFFF00, and r2 = 0x00029 F05 in a 32-bit system. Initially the N, Z, C, V flags ADD r3, r0, r2 SUBS r3, ro, r0 а. b. ADDS r3, r0, r2 LSL r3, r0, #1 С. d.
%oV li. MOV BL,AL has the following instruction format feilds REG= 000 MOD=11 R/M=011 , the byte 2 will be : O 11000001 C3 11001001 О зс Machine language instruction format consist of: * Operand code field Operation code field and operand field Operand field O None of above
In this implementation, each instruction is provided with its own data independently of how other instructions acquire theirs. We insert a(n): A Multiple Input/Output B The Case of Many Pieces of Information or Directions C Unique Information Only One D Several Insts From One
Computer Science Given the machine code, identify the instruction line or command line. Use CAPITAL LETTERS . No spaces in the operand side. NO need to include "H" for any immediate or displacement value. e.g. MOV AX,BX GIVEN: 00001111 10110111 00010110 10101011 00111111
Here is an LC-3 assembly language program: .ORIG x30e5 A LD R7, C LD R7, E LD R7, B D LD R7, A E LD R7, E HALT .END The following bit pattern is loaded into R7 by one of these instructions: 0010111111111110 What is the label (argument column) of the instruction which loads this value into R7 ?
Q1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000H to 3009H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending each of the required bytes, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes. The solution must be integrated and include the calculation of the baudrate delay time Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)