Problem 28: Find the average power loss and power factor for each of the circuits whose input current and voltage are as follows: v = 60 sin (wt + 30°) i = 15 sin (wt + 60°). v = -50 sin (wt – 20°) a. b. i = -2 sin (wt – 20°). v = 50 sin (wt + 80°) i = 3 cos (wt – 20°) C.

Problem 28: Find the average power loss and power factor for each of the circuits whose input current and voltage are as follows: v = 60 sin (wt + 30°) i = 15 sin (wt + 60°). v = -50 sin (wt – 20°) a. b. i = -2 sin (wt – 20°). v = 50 sin (wt + 80°) i = 3 cos (wt – 20°) C.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...

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Concept explainers

HVDC

HVDC stands for high voltage direct current in the electric power transmission system. The high voltage direct current system uses direct current (DC) for the transmission of electrical power through transmission lines in contrast with the alternating current that is the AC system. The HVDC is used to transmit bulk power point-to-point through long distances transmission lines. Power is rapidly transferred because the efficiency of transmission lines is greatly increased over long distances due to HVDC lines.

Question

Problem 28: Find the average power loss and power factor for each of the circuits whose input
current and voltage are as follows:
v = 60 sin (wt + 30°)
i = 15 sin (wt + 60°)
a.
v = -50 sin (wt – 20°)
b.
i = -2 sin (wt – 20°)
v = 50 sin (wt + 80°)
C.
i = 3 cos (wt – 20°)

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