Problem 21: CH14O2 (a phenol) 300 MHz 'H NMR In CDC13 1H, disappears on D₂O shake 2H 2H 2H, triplet 9 8 7 6 5 2H, quintet 2H, sextet 3H, triplet 4 3 2 1 0 11

а. Perform one sample calculation: to calculate AE in J and wavelength A in nm and complete the following table : Show one sample calculation 4 3 1 ΔΕ AE = ΔΕ - ДЕ - AE = 2.66x10-20 J 1 = 7470 nm ДЕ — ΔΕ- AE = AE = 4 AE = ДЕ — AE = X X 3 ДЕ — AE = X X = X 2 ΔΕ- X X X Then use the following table to determine the corresponding electronic transition: Wavelength Color 656.2 red 486.1 blue-green 434.0 blue-violet 410.1 violet 2.

3V 1 U = 2n² v? w?dw (Н. W.) %3D hw eKBT-1

In a few sentences, explain how you know that E(r)=(kQs/r2)r (Eq. 24.3) is consistent with Figure 24.4C. E(r)=(kQs/r2)r