Problem 21: CH14O2 (a phenol) 300 MHz 'H NMR In CDC13 1H, disappears on D₂O shake 2H 2H 2H, triplet 9 8 7 6 5 2H, quintet 2H, sextet 3H, triplet 4 3 2 1 0 11

Q: - ヘ How?

A: Theory :

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Q: 3 Given that 1 cm 1 millilitre Convert 508 litres to m3 Answer: 0.508

A: So   1 m3 = 106 cm3  and,  Realtion between liter and millilitre is   1 liter = 103 mili liter

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A: Have a look dear

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A: mass of box = m = 10 kg co efficient of friction = 0.7 acceleration = a = 6 m/s2

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