Problem 2.20 One of these is an impossible electrostatic field. Which one? (a) E=k[xy£+2yzý+3xzZ]; (b) E= k[y² + (2xy + z²)ŷ + 2yz 2]. Here k is a constant with the appropriate units. For the possible one, find the poten- tial, using the origin as your reference point. Check your answer by computing VV. [Hint: You must select a specific path to integrate along. It doesn't matter what path you choose, since the answer is path-independent, but you simply cannot integrate unless you have a definite path in mind.]
Problem 2.20 One of these is an impossible electrostatic field. Which one? (a) E=k[xy£+2yzý+3xzZ]; (b) E= k[y² + (2xy + z²)ŷ + 2yz 2]. Here k is a constant with the appropriate units. For the possible one, find the poten- tial, using the origin as your reference point. Check your answer by computing VV. [Hint: You must select a specific path to integrate along. It doesn't matter what path you choose, since the answer is path-independent, but you simply cannot integrate unless you have a definite path in mind.]
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![Problem 2.20 One of these is an impossible electrostatic field. Which one?
(a) E= k[xy x + 2yz y + 3xz 2];
(b) E= k[y² + (2xy + z²)ŷ + 2yz2].
Here k is a constant with the appropriate units. For the possible one, find the poten-
tial, using the origin as your reference point. Check your answer by computing VV.
[Hint: You must select a specific path to integrate along. It doesn't matter what path
you choose, since the answer is path-independent, but you simply cannot integrate
unless you have a definite path in mind.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F780135a8-f701-479c-be02-38c3a3de7347%2F0a7703f3-a599-4e9e-8c3a-f9f2298bada8%2Fr7tk3xl_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 2.20 One of these is an impossible electrostatic field. Which one?
(a) E= k[xy x + 2yz y + 3xz 2];
(b) E= k[y² + (2xy + z²)ŷ + 2yz2].
Here k is a constant with the appropriate units. For the possible one, find the poten-
tial, using the origin as your reference point. Check your answer by computing VV.
[Hint: You must select a specific path to integrate along. It doesn't matter what path
you choose, since the answer is path-independent, but you simply cannot integrate
unless you have a definite path in mind.]
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