Problem 2. The square foundation shown in Figure below rests in homogeneous soft clay layer. Subsurface exploration and laboratory testing found that the soil's effective cohesion is 30 kN/m². The groundwater table is far below the ground surface and will not affect the bearing capacity. The unit weight of clay above the groundwater table is 16.5 kN/m³. Using Terzaghi's bearing capacity theory, determine the ultimate bearing capacity of the soil. Assume general shear failure. If the factor of safety for bearing capacity is 3.5, calculate the allowable bearing capacity. B =1.2 m and Df = 1.0 m. Df Di 7 7sat B Ground surface Groundwater table V.

Problem 2. The square foundation shown in Figure below rests in homogeneous soft clay layer. Subsurface exploration and laboratory testing found that the soil's effective cohesion is 30 kN/m². The groundwater table is far below the ground surface and will not affect the bearing capacity. The unit weight of clay above the groundwater table is 16.5 kN/m³. Using Terzaghi's bearing capacity theory, determine the ultimate bearing capacity of the soil. Assume general shear failure. If the factor of safety for bearing capacity is 3.5, calculate the allowable bearing capacity. B =1.2 m and Df = 1.0 m. Df Di 7 7sat B Ground surface Groundwater table V.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: (c) The shear strength of soil collected 4m below ground surface and tested under consolidated…

A: Comparing the given equation of Shear stress with standard equation:

Q: 1. For the square foundation below determine: a) ultimate settlement and b) settlement after 140…

A: Given: A clay layer of thickness 8ft is overlained by a sand layer of thickness 20 ft. Water table…

Q: 1 For the square foundation below determine: a) ultimate settlement and b) settlement after 140 days…

A: Ultimate Settlement=Sult=0.126 ft Settlement after 140 days=S140=0.087 ft Saturated unit weight of…

Q: A plan of a foundation 1 m x 2 m is shown in Figure 4-2. a. Estimate the consolidation settlement of…

A: Given DataFoundation dimensions: 1 m×2 m Net stress increase, q0 = 170 kN/m2 Sand layers:Upper sand:…

Q: Mohr Circle - At a point in the ground, a soil experiences a vertical effective stress of 3000 psf…

Q: = Figure 2 shows a rectangular shallow foundation. The foundation measures 1.5 m x3 m (B x L) in…

A: Average effective stress on the clay layer due to applied foundation load is 24 KN/m2.Determine the…

Q: Q = 900 kN Ground surface Df = 1 m Ground water table LxB = 3m x 2m eo = 0.5, c = 0.35, c, 0.06,…

A: The depth of the footing(Df)=1 m, The surcharge on the footing(Q)=900 kN, Length of the footing(L)=3…

Q: O A. Tresca failure criterion. O B. None of the filure criterion models. 2 C. Mohr-Coulomb failure…

A: Question 15- Option C Mohr failure criteria is used. In this test mohr circle is plotted at…

Q: 1. ) For the square foundation below determine: a) ultimate settlement and b) settlement after 140…

A: Findultimate settlementthe final settlement and settlement after 140 days

Q: A normally consolidated clay layer settled by 20 mm when the effective stress was increased from 25…

Q: The results of a consolidated undrained test, in which o3 = 392 kN/m², on a normally consolidated…

A: Given : Results of a consolidated undrained test on a normally consolidated clay σ3 =…

Q: A3-m thickness of compacted earth fill is placed across an area as preparation for constructing an…

A: The equipment load of 500 KN will not act as a point load as foundation will disperse the coming…

Q: A square column foundation with base of 1.40 m is shown in the figure. It carries an axial load of…

Q: An oil storage tank 35 m in diameter is located 2 m below the surface of a deposit of clay 32 m…

Q: 8.4 A rectangular foundation is shown in Figure P8.2, given B= 2 m, L=4m q= 240 kN/m², H= 6m, and D;…

Concept explainers

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.

Question

Problem 2. The square foundation shown in Figure below rests in homogeneous soft clay layer.
Subsurface exploration and laboratory testing found that the soil's effective cohesion is 30 kN/m².
The groundwater table is far below the ground surface and will not affect the bearing capacity. The
unit weight of clay above the groundwater table is 16.5 kN/m³. Using Terzaghi's bearing capacity
theory, determine the ultimate bearing capacity of the soil. Assume general shear failure. If the
factor of safety for bearing capacity is 3.5, calculate the allowable bearing capacity. B =1.2 m and
Df = 1.0 m.
Df
D₁
7
7 sat
B
Ground surface
Groundwater table

Expert Solution

Step 1

Given,

c = 30 kPa

$γ$ = 16.5 kN/m³

FS = 3.5

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Estimate the ultimate consolidation settlement under the centerline of a 25 x 25 meter mat foundation. The mat is 1.5 meter thick reinforced concrete (ϒconcrete = 23.6 kN / m3), and the average stress on the surface of the slab is 125 kPa. The soil profile is shown in the figure below. Lab testing on samples of the clay showed that the clay is normally consolidated and that Cc = 0.40, Cr = 0.03, and eo = 1.13. Neglect any settlements due to the sand layer. Divide the clay layer into four thinner layers of thickness 2.0, 2.0, 3.0, and 3.0 meters.
Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.
Two foundations are located next to each other as follows. Determine the stress increase on a horizontal plane (i.e. - the increase in vertical stress) beneath Point A at a depth of 3 m below the ground surface. The foundations are bearing on the ground surface. 3 m- +2.5 m -6 m 5 m A O= 90 kPa = 120 kPa 6 m
11.19 Refer to Figure 11.45. A square footing, 2 x 2 m in size, supports a column load of 300 kN. The soil characteristics are given in the figure. Field monitoring indi- cated that the foundation settlement was 19 mm during the first 12 months. a. Estimate the average stress increase in the clay layer due to the applied load. b. Estimate the primary consolidation settlement. c. What is the degree of consolidation after 12 months? d. Estimate the coefficient of consolidation for the pressure range. e. Estimate the settlement in 24 months. 300 kN 1m 2m x 2 m Ya = 14 kN/m3 I m Yu = 17 kN/m 24% G, = 2.74 LL = 46 2 m o'= 40 kN/m² C, = 1/5C. Sand Clay Figure 11.45 O Cengrge learring 2014