Problem 2. Someone makes a claim that the probability of bit error, p. fora certain unit is less than 10-5. Based on sample data with n = 10,000,000,80 bit errors were found. We wish to test the claim that the probability ofbit error is less than 10-5 using a significance level of 0.05.a. What is the null hypothesis?b. What is the alternate hypothesis?c. What is the critical value?d. Test the null hypothesis by computing the test statistic Z. What isyour value for Z?e. What is the P-value?f. Based on the critical value or the P-value should we reject or fail toreject the null hypothesis?

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Answered: Problem 2. Someone makes a claim that…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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1.
15. In a test of hypothesis about a mean, the critical value for a = 0.05 in a two-tailed test is 1.96. The resulting test statistic value from the sample data is -2.75. Which is the correct decision to make based on the given information? A. Reject the null hypothesis B. Change the alternative hypothesis O C. Fail to reject the null hypothesis D. Redefine the hypothesis
1. On a certain hearing ability test, the mean is 300 and the standard deviation is 20. Thebetter you can hear, the higher your score. Can people who clean their ears frequentlyhear better than others? You take a sample of 31 people who clean their earsfrequently. Their sample mean test score is 308. Do a hypothesis test with α = 0.01.H 0 : People who clean their ears regularly hear at the same level that everyone elsedoes: µ = 300.H 1 : People who clean their ears regularly hear better than others: µ > 300.a. Check to see if the null hypothesis sampling distribution is normal. Keep in mindwhether you are dealing with means or proportions. b. Draw the null hypothesis sampling distribution (a normal curve). Label its center. c. Calculate your test statistic and draw it on your null hypothesis curve. This is justyour sample statistic ( or ) converted to a Z-score on your null hypothesis samplingdistribution. Make sure you are using the appropriate SE formula! Use forproportions…
18. With respect to the chi-square test, a p value of 0.034 means there is a 3.4% probability that the deviation of the observed value from the expected value is due to chance and a 96.6% probability that this is not due to chance. True False
4. Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. Net weights actually vary slightly from bag to bag and are Normally distributed with mean μ. A representative of a consumer advocate group wishes to see if there is any evidence that the mean net weight is less than advertised and so intends to test the hypotheses Ho: = 14, Ha: < 14. To do this, he selects 16 bags of this brand at random and determines the net weight of each. A Type I error in this setting would mean (a) concluding that the bags are being underfilled when they actually aren't. (b) concluding that the bags are being underfilled when they actually are. concluding that the bags are not being underfilled when they actually are. (d) concluding that the bags are not being underfilled when they actually aren't. (e) none of these
4
4. The population from which the sample in problem 3 was randomly drawn has a μ of 51 and a o of 14. What is the probability of obtaining a random sample of 25 scores with a mean (a) below 46? (b) below 46 or above 567 5 David's uncle is building rouse on land that
Question II. The following two-by-three table gives the sample proportions corresponding to different combinations of factor categories (for example, 28% of the sample fell in the cell representing category 1 of factor A and category 3 of factor B). A B .13 .19 .28 .07 .11 .22 II(a). Suppose that the sample size is n=100. Carry out a chi-squared test of independence at the 10% significance level. Make sure to state the null and alternative hypotheses, degrees of freedom, the value of your test statistic, the p-value, and the final conclusion. II(b). Now, suppose that n=1000 and repeat part 3(a). II(c). Find the smallest value of n that will result in rejection of the null hypothesis of part 3(a) at 10% level. Start by finding the appropriate x² statistic (which will depend on the n).

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