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Problem 2. A pipeline consist of a successive lengths of diameters equal to 250mm, 300mm,350mm with continuous flow through the line of 0.250 m3/sec of water. Compute the mean velocity of each pipe. Q

Problem 2. A pipeline consist of a successive lengths of diameters equal to 250mm, 300mm,350mm with continuous flow through the line of 0.250 m3/sec of water. Compute the mean velocity of each pipe. Q

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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For pipe 2: Q2 = A2 V2 = 0.25m³/sec Solving for v2: Q2 V2 = 0.25 A2 n( 0.300)2 V2 = 3.536m/sec(answer) For pipe 3: Solving for v3: Q3 V3 = П(350)2 0.25 A3 V3= 2.598m/sec( answer)
Transcribed Image Text:For pipe 2: Q2 = A2 V2 = 0.25m³/sec Solving for v2: Q2 V2 = 0.25 A2 n( 0.300)2 V2 = 3.536m/sec(answer) For pipe 3: Solving for v3: Q3 V3 = П(350)2 0.25 A3 V3= 2.598m/sec( answer)
Problem 2. A pipeline consist of a successive lengths of diameters equal to 250mm, 300mm,350mm with continuous flow through the line of 0.250 m/sec of water. Compute the mean velocity of each pipe. Q 1 2 Solution: Since the flow is continuous, from continuity of flow: Q1=Q2 = Q3 = Q = 0.250m³/sec. For pipe 1: Q1 = A¡V1 = 0.25m³/sec solving for v,: Q1 П(0.250)2 0.25 V1 = A1 V1 = 5.093m/sec(answer)
Transcribed Image Text:Problem 2. A pipeline consist of a successive lengths of diameters equal to 250mm, 300mm,350mm with continuous flow through the line of 0.250 m/sec of water. Compute the mean velocity of each pipe. Q 1 2 Solution: Since the flow is continuous, from continuity of flow: Q1=Q2 = Q3 = Q = 0.250m³/sec. For pipe 1: Q1 = A¡V1 = 0.25m³/sec solving for v,: Q1 П(0.250)2 0.25 V1 = A1 V1 = 5.093m/sec(answer)
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