PROBLEM 2 - The wooden block (mass m= 0.54321 kg) is released from rest at A by a compressed spring (compressed length 0.6 m, undeformed length 1 m, spring constant k = 150 N/m). The block is allowed to slide through the rough horizontal surface (A to B), then along the smooth circular ramp (B to C, central angle 0 = 45.6°), until the block is released after point C. Calculate the speed of the block at points B and C. Also, what is the magnitude of the normal force exerted to the block just before the block leaves the ramp? Neglect the geometry of the block. NOTE: Use Work-Energy Method to solve for the speeds; use FMA Method to compute for the normal force. Use g== 9.81 m/s? = 32.2 ft/s? 0.6 m 1 m path of the block smooth surface B rough surface Hs = 0.35 Hk = 0.25 A 1.5 m 1.5 m
PROBLEM 2 - The wooden block (mass m= 0.54321 kg) is released from rest at A by a compressed spring (compressed length 0.6 m, undeformed length 1 m, spring constant k = 150 N/m). The block is allowed to slide through the rough horizontal surface (A to B), then along the smooth circular ramp (B to C, central angle 0 = 45.6°), until the block is released after point C. Calculate the speed of the block at points B and C. Also, what is the magnitude of the normal force exerted to the block just before the block leaves the ramp? Neglect the geometry of the block. NOTE: Use Work-Energy Method to solve for the speeds; use FMA Method to compute for the normal force. Use g== 9.81 m/s? = 32.2 ft/s? 0.6 m 1 m path of the block smooth surface B rough surface Hs = 0.35 Hk = 0.25 A 1.5 m 1.5 m
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Transcribed Image Text:PROBLEM 2 – The wooden block (mass m 0.54321 kg) is released from rest at
A by a compressed spring (compressed length 0.6 m, undeformed length 1 m,
spring constant k = 150 N/m). The block is allowed to slide through the rough
horizontal surface (A to B), then along the smooth circular ramp (B to C, central
angle 0 = 45.6°), until the block is released after point C. Calculate the speed of
the block at points B and C. Also, what is the magnitude of the normal force
exerted to the block just before the block leaves the ramp? Neglect the
%3D
geometry of the block.
NOTE: Use Work-Energy Method to solve for the speeds; use FMA Method to
compute for the normal force. Use g== 9.81 m/s = 32.2 ft/s?
0.6 m
1 m
path of the block
smooth surface
B
rough surface
Hs = 0.35
A
C
Hx = 0.25
1.5 m
1.5 m
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