Problem 2: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a combined mass of 97.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and the snow is 0.100. w 60° Otl Part (a) How much work, in joules, is done by friction as the sled moves 30.5 m along the hill? W = sin() cos() tan() 7 8 9. HOME cotan() asin() acos() E 4 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() + END - Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) How much work, in joules, is done by the rope on the sled over this distance? Part (c) What is the work, in joules, done Part (d) What is the net work done on the sled, in joules? the gravitational force on the sled?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 2: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a
combined mass of 97.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The
coefficient of kinetic friction between the sled and the snow is 0.100.
w
60°
©tl
Part (a) How much work, in joules, is done by friction as the sled moves 30.5 m along the hill?
We=
sin()
cos()
tan()
7
8
9.
HOME
cotan()
asin()
acos()
E
4
atan()
acotan()
sinh()
1
2
3
cosh()
tanh()
cotanh()
+
END
-
Degrees
O Radians
VO BACKSPACE
DEL
CLEAR
Submit
Hint
Feedback
I give up!
Part (b) How much work, in joules, is done by the rope on the sled over this distance?
Part (c) What is the work, in joules, done
Part (d) What is the net work done on the sled, in joules?
the gravitational force on the sled?
I I I
Transcribed Image Text:Problem 2: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a combined mass of 97.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and the snow is 0.100. w 60° ©tl Part (a) How much work, in joules, is done by friction as the sled moves 30.5 m along the hill? We= sin() cos() tan() 7 8 9. HOME cotan() asin() acos() E 4 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() + END - Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) How much work, in joules, is done by the rope on the sled over this distance? Part (c) What is the work, in joules, done Part (d) What is the net work done on the sled, in joules? the gravitational force on the sled? I I I
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