Problem # 2 On random packetization (perhaps a variation on a familiar theme...):A large file, whose size is c bytes, is randomly divided into two smaller packets for streamingover the network. The size in bytes of the first packet, is random variable X, with PDFfx(x) = ½ x, x = [0, c]. The second packet contains the remainder of the file, and its size inbytes is random variable Y.a) Find the expected size (in bytes) of the larger packet.b) Find the correlation, covariance and correlation coefficient of X and Y.c) Are X and Y uncorrelated, independent, orthogonal?d) Find the PDF of Z, the difference in size between the larger and the smaller packet, Z= max{X, Y} – min{X, Y}.

Answered: Problem # 2 On random packetization…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 7: Let X be a random variable such that E(X – 2)² = 10 and E(X+1)² = 4, then а. Е(X) b. Е(X) %3D с. Е (X) %3D d. E(X) =
QUESTION 5 An experiment was conducted to evaluate the effectiveness of a treatment for tapeworm in the stomachs of sheep. A random sample of 60 worm-infected lambs of approximately the same age and health was randomly divided into two groups. Thirty of the lambs were injected with the drug and the remaining thirty were left untreated. After a 6-month period, the lambs were slaughtered and the number of worms in the lamb of the stomach were counted. The drug-treated sheep had a mean of 24.67 worms with a standard deviation of 13.78. The untreated sheep had a mean of 37.82 worms with a standard deviation of 18.21. Assuming the true variances cannot be assumed equivalent, which of the following would be the correct way to calculate a t test for a two-tailed hypothesis test? OA. 24.67-37.82 O B. о с. t ¹0= 13.78 18.21 30 30 24.67-37.82 + (13.78) 2 30 + 24.67-37.82 + (18.21) ² 30 13.78 18.21 60 60 + 24.67-37.82 (13.78) 2 60 (18.21) 2 60
QUESTIONS 1-5. Data in the table below were collected on a new test for the diagnosis of COVID-19 in a sample of 100,000 adults from the United States. Answer questions 1-5 based on these data. Status COVID-19 Present COVID-19 Absent Positive Test 9,500 4,500 Negative Test 500 85,500 4. What is the Positive Predictive Value (PPV)? O 0.90 O 0.75 O 0.68 O 0.50
Problem 7 Let X ~ Poisson(a) and Y ~ Poisson(3) be two independent random variables. Define a new random variable as Z = X +Y. Find the PMF of Z.
Question 11 C 0/1 pt 53 99 Details A CBS News poll conducted June 10 and 11, 2006, among a nationwide random sample of 651 adults, asked those adults about their party affiliation (Democrat, Republican or none) and their opinion of how the US economy was changing ("getting better," "getting worse" or "about the same"). The results are shown in the table below. better same worse Republican 38 104 44 Democrat 12 87 137 none 21 90 118 Express your answers as a decimal and round to the nearest 0.001 (in other words, type 0.123, not 12.3% or 0.123456). If we randomly select one of the adults who participated in this study, compute: P(Democrat) = P(better) = P(better | Democrat) = P(Democrat |better) = P(Democrat and better) = 2Calculator Submit Question
Problem #2: If two loads are applied to a cantilever beam as shown in the figure below, the bending moment at 0 due to the loads is a1X₁ + a₂X₂. Problem =2(a) Problem =2(b) X1 Problem #2(c): a X₂ 9 Suppose that X₁ and X2 are independent random variables with means 2 and 5 kips, respectively, and standard deviations 0.7 and 1.5 kips. respectively. Suppose that a₁ = 3 ft and a2 = 10 ft. (a) Find the expected value of the bending moment. (b) Find the standard deviation of the bending moment. (c) If X₁ and X₂ are normally distributed, what is the probability that the bending moment will exceed 82 kip-ft? answer correct to 4 decimals answer correct to 4 decimals

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