Answer fast and do calculation Problem 2: Determine the station of the PT in a horizontal curveOn a roadway with two 12 ft lanes, a horizontal curve is designed for 35 mph witha 4% superelevation. It is known that A = 2As. The PI of the curve is at station 30 +00. What is the station of the PT of the curve?R =ftT =ftL =Sta PC =Sta PT =ft

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Answered: Problem 2: Determine the station of the…

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter15: Geometric Design Of Highway Facilities

Section: Chapter Questions

Problem 21P

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6. The following figure shows a two-lane road with curve 1 having a horizontal curve length of 1,850.00 ft and radius of 1,200.00 ft. Curve 2 has a horizontal curve length of 1,410.00 ft and a radius of 900.00 ft. The road has a design speed of 40 mph and the maximum superelevation is 6%. PC1 is at station 58+55.00 and PT2 is at station 92+15.00. Under these conditions, is this sequence of curves sufficiently designed (Hint: does it have non-overlapped tangent)? If they overlap under standard methods of superelevation placement, how much do they overlap? (20 pts) PC1 PT1 Curve 1 PT2 Curve 2 PC2
A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of PI: 2700 = 10.65 fs= 0.12 e = 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deﬂection angle and chord length to the ﬁrst even 100 ft station.
Determine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255', Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed=60 mph, max superelevation=8% 8) The station of the NC is: O 8+12.5 8+90 8+92.5 O 11+22.5 O 12+00
PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3% The high point of the curve is at station ? Note: I need right solution.. Don't copy from other expert solution.
Determine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255', Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed%3D60 mph, max superelevation=8% 6) The length in full superelevation, in ft, is: O 790 O 1100 O 1410 O 1875 O 2075
Determine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255, Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed=60 mph, max superelevation=8% 7) The difference in elevation of LEP and REP at PC/PT, in ft, is: O 0.42 O 1.68 O 2.52 O 3.36
PROBLEM #1) An existing highway with bearing of N 20deg E to be connected to another highway, with bearing of N 75deg E, by a 4-degree simple curve. What length of curve is required? (SIMPLE AND COMPOUND CURVES) *PLEASE REFER TO THE FORMULAS BELOW*
Design a horizontal curve for the highway by computing the radius and stationing of PC and PT using the following data, # of lanes = 2 Width per lane = 12 ft Pl is at station 120+20 Design speed is 60 mi/h Superelevation = 0.06 ft/ft Central angle of the curve = 37 degrees
ans No. 1 only. asap
2
3.48 A horizontal curve is being designed for a new two-lane highway (12-ft lanes). The PI is at station 250 + 50, the design speed is 65 mi/h, and a maximum superelevation of 0.07 ft/ft is to be used. If the central angle of the curve is 38 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT. 3.49 You are nal
Problem 2 A reversed curve is o connect two tangents which is parallel to each other and are 200 m apart with directions due east. There is an intermediate tangent of 200 m in between the reversed curve and the horizontal distance of P.C and P.T. measured parallel to the tangents is 800 m long. The P.C. of the reversed curve is on the upper tangent while the P.T. of the reversed curve is at the lower tangent. 1. Determine the tangent distance of each curve in meters. 2. Determine the common radius of the reverse curves.

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