Problem 2: A rocket is launched from the ground, straight up, from rest. The expelling gases from the bottom of the rocket provide it with a constant upward acceleration a. After 20 sec, the rocket reaches a height of 6500 m. At this point, the rocket depletes its fuel supply and the engines of the rocket are no longer working. At this point, the rocket goes into free fall, with an acceleration of -9.8 m/sec?. The left part of the figure below applies to parts (a)-(b). (a) What is the rocket's initial upward acceleration a? (b) What is the rocket's speed v, 20 sec after take-off? Hint: The answer is v = 650 m/sec. For parts (c)-(d), the rocket engines are now off. We will redefine the time to t = 0. The final properties for when the engines were on make the initial properties for when the engines are off: yo = 6500 m, vo = 650 m/sec, and the acceleration is now a = -g, with g = 9.8 m/sec2. The right part of the figure below applies to parts (c)-(d). (c) What is ymaz, the largest height the rocket reaches? (d) What is the time t it takes the rocket to reach ymaz?

Problem 2: A rocket is launched from the ground, straight up, from rest. The expelling gases from the bottom of the rocket provide it with a constant upward acceleration a. After 20 sec, the rocket reaches a height of 6500 m. At this point, the rocket depletes its fuel supply and the engines of the rocket are no longer working. At this point, the rocket goes into free fall, with an acceleration of -9.8 m/sec?. The left part of the figure below applies to parts (a)-(b). (a) What is the rocket's initial upward acceleration a? (b) What is the rocket's speed v, 20 sec after take-off? Hint: The answer is v = 650 m/sec. For parts (c)-(d), the rocket engines are now off. We will redefine the time to t = 0. The final properties for when the engines were on make the initial properties for when the engines are off: yo = 6500 m, vo = 650 m/sec, and the acceleration is now a = -g, with g = 9.8 m/sec2. The right part of the figure below applies to parts (c)-(d). (c) What is ymaz, the largest height the rocket reaches? (d) What is the time t it takes the rocket to reach ymaz?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

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Problem 2: A rocket is launched from the ground, straight up, from rest. The expelling gases from the
bottom of the rocket provide it with a constant upward acceleration a. After 20 sec, the rocket reaches
a height of 6500 m. At this point, the rocket depletes its fuel supply and the engines of the rocket are
no longer working. At this point, the rocket goes into free fall, with an acceleration of –9.8 m/sec2.
The left part of the figure below applies to parts (a)-(b).
(a) What is the rocket's initial upward acceleration a?
(b) What is the rocket's speed v, 20 sec after take-off? Hint: The answer is v = 650 m/sec.
For parts (c)-(d), the rocket engines are now off. We will redefine the time to t = 0. The final properties
for when the engines were on make the initial properties for when the engines are off: y0 = 6500 m,
vo = 650 m/sec, and the acceleration is now a = -g, with g = 9.8 m/sec?. The right part of the figure
below applies to parts (c)-(d).
(c) What is ymaz, the largest height the rocket reaches?
(d) What is the time t it takes the rocket to reach ymaz?
ул
Engines Off
Parts c, d
ул
v = 0 m/sec
Ymax =?.
t =?
Engines On
Parts a, b
t = 20 sec
y = 6500 m
v =?
Redefine as t = 0
Yo = 6500 m
vo = 650 m/sec
a = -g
g = 9.8 m/sec?
%3D
t = 0
a =?
Yo = 0.
vo = 0 m/sec

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