Problem #2: A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of its digits at even places is either 0 or divisible by 11. For example, for 2547039: (Sum of digits at odd places) - (Sum of digits at even places) = (9 + 0+ 4+ 2) - (3 +7+ 5) = 0 So 2547039 is divisible by 11. But for 13165648: (Sum of digits at odd places) - (Sum of digits at even places) = (8 + 6 + 6+ 3) - (4 + 5+1+ 1) = 12 12 is not divisible by 11 so 13165648 is also not divisible by 11. Sample run: Give your number: 13165648 Total is: 12 13165648 is not divisible by 11.

Problem #2: A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of its digits at even places is either 0 or divisible by 11. For example, for 2547039: (Sum of digits at odd places) - (Sum of digits at even places) = (9 + 0+ 4+ 2) - (3 +7+ 5) = 0 So 2547039 is divisible by 11. But for 13165648: (Sum of digits at odd places) - (Sum of digits at even places) = (8 + 6 + 6+ 3) - (4 + 5+1+ 1) = 12 12 is not divisible by 11 so 13165648 is also not divisible by 11. Sample run: Give your number: 13165648 Total is: 12 13165648 is not divisible by 11.

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter13: Overloading And Templates

Section: Chapter Questions

Problem 33SA

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Question

Problem #2: A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of
its digits at even places is either 0 or divisible by 11.
For example, for 2547039:
(Sum of digits at odd places) - (Sum of digits at even places) = (9 + 0 + 4 +2) - (3 +7 + 5) = 0
So 2547039 is divisible by 11.
But for 13165648:
(Sum of digits at odd places) - (Sum of digits at even places) = (8 + 6 + 6 + 3) - (4 + 5 +1 + 1) = 12
12 is not divisible by 11 so 13165648 is also not divisible by 11.
Sample run:
Give your number: 13165648
Total is: 12
13165648 is not divisible by 11.

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