Problem 18. A particle moves along a straight line and its velocity depends on time as v = 3t – t2. Here v is in m/s and t in second. Find: (b) average speed for first five seconds.
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A: a) for first interval Vavg = s/t = 15/2.5 = 6 m/s For 2nd interval Vavg = -3/1.75 = -1.71 m/s…
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Q: Problem 1: An object is thrown straight up with an initial velocity of 17 m/s. Part (a) How high…
A: The given data are as follows: The object is thrown straight up. The initial velocity, u = 17 m/s
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Q: A bicyclist in the Tour de France crests a mountain pass as he moves at 15 km/h. At the bottom, 4.0…
A: Given: initial velocity=u=15km/h u=(15km/h)×1000m1km×1h3600su=4.17m/s final velocity=v=65 km/h…
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A: Initial speed of the cheetah is v0 = 0Distance travelled by the cheetah is x=45m
Q: The position of an object as a function of time is given by x(t) = bt3 - ct² + et - f, where b = 3.4…
A: Aberage acceleration is given by a = [v(at given time) - v(t=0)]/[given time(t) - (t=0)] First we…
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A: Given: initial velocity at t = 0 , u = 15 m/s acceleration, a = (0.5 t + 4) m/s2 time, t = 4…
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A: Acceleration of motorcycle (a) = 2.83 m/s2
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- Problem 4: A particle moving along a straight path has an acceleration defined by a = 0.6s + 3.6 ft/s², where s is in feet. If the particle's speed is 1.2 ft/s at s = 0, find its speed when s = 8 feet.The acceleration of a particle as it moves along a straight line is given by a = (2t - 1) m/s? , where t is in seconds. Determine the particle's position when t = 6 seconds.Nerve impulses in a human body travel at a speed of about 100 m/s. Suppose a person accidentally steps barefoot on a pebble. About how much time does it take the nerve impulse to travel from the foot to the brain (in s)? Assume the person is 1.60 m tall and the nerve impulse travels at uniform speed.
- Chapter 02, Problem 10 In reaching her destination, a backpacker walks with an average velocity of 1.26 m/s, due west. This average velocity results, because she hikes for 6.62 km with an average velocity of 2.54 m/s due west, turns around, and hikes with an average velocity of 0.381 m/s due east. How far east did she walk (in kilometers)? dw VE West East dɛ Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show WorkA brick is dropped from the roof of a tall building. After it has been falling for a few seconds, it falls 41.0 mm in a 1.00-ss time interval.What distance will it fall during the next 1.00 s? Ignore air resistance.The position of a particle moving along the x axis depends on the time according to the equation x = ct - btº, where x is in meters and t in seconds. Let c and b have numerical values 2.5 m/s4 and 1.2 m/s³, respectively. From t = 0.0 s tot = 2.5 s, Find its velocity at times (b) 1.O s, (c) 2.0 s, (d) 3.0 s, and (e) 4.0 s. Find its acceleration at (i) 4.0 s.
- A skydiver falls d1=355m in t1=8.7s before opening her parachute. After the chute opens, she falls an additional d2=780m in t2=116s. Calculate the skydiver’s average speed, v avg in meters per second, during the entire fall.The function x (t) = -2.1le-1.93t describes the position, in meters, of a particle on the x-axis as a function of time t, in seconds. Find the particle's velocity at time t = 3.05 s.A rock parrot (Neophema petrophila) flies 37 m south and then 49 m west, in a total time of 31 minutes. What is its average velocity from the starting position? Enter only the numerical part of your answer (in km/h) to two significant figures.
- A particle moves along the x-axis according to the equation s = 2 + 3t – t2, where s is in meters and t is in seconds. At t = 3 s, find (a) the position of the particle, (b) its velocity, & (c) acceleration.The velocity (in m/s) of a particle is given by v(t) = 2t- 6 where t is the time in seconds. During the interval 0A spacecraft is always headed north, starts at 90m/s, and maintains a constant acceleration of 0.7m/s2 for 3.9 min. What is it's displacement during this time? Round your answer to 3 significant digits, and don't forget the units.SEE MORE QUESTIONS