11. Sir Lost-a-Lot dons his armor and sets out from the castle onhis trusty steed (Fig. P12.11). Usually, the drawbridge is low-ered to a horizontal position so that the end of the bridgerests on the stone ledge. Unfortunately, Lost-a-Lot's squiredidn't lower the drawbridge far enough and stopped it at20.0° above the horizontal. The knight and his horsestop when their combined center of mass is d = 1.00 m fromthe end of the bridge. The uniform bridge is l = 8.00 mlong and has mass 2 000 kg. The lift cable is attached to thebridge 5.00 m from the hinge at the castle end and to apoint on the castle wall h = 12.0 m above the bridge. Lost-a-Lot's mass combined with his armor and steed is 1 000 kg.Determine (a) the tension in the cable and (b) the horizon-tal and (c) the vertical force components acting on thebridge at the hinge.h Problem 11b asks for the x-component of the forceon the bridge due to the hinge. Answer inNewtons. This time, the computer will choose thenumbers.• 0 = 19°• d = 0.8 m%3D• e = 8 m%3DM = 2300 kg%3DCable's distance from the hinge (5 m in the text)is c = 6.4 m• h = 12 m• Lot's mass (1000 kg in the text) is m = 1200 kg%3D

θ = 19° d = 0.8 m l = 8 m M = 2300 kg c = 6.4 m h =12 m m = 1200 kg To find = a) Tension in the…

Problem 11b asks for the x-component of the force on the bridge due to the hinge. Answer in Newtons. This time, the computer will choose the numbers. e = 19° • d = 0.8 m %3D %3D e = 8 m • M = 2300 kg • Cable's distance from the hinge (5 m in the text) is c = 6.4 m •h = 12 m • Lot's mass (1000 kg in the text) is m = 1200 kg %3D %3D

Problem 11b asks for the x-component of the force on the bridge due to the hinge. Answer in Newtons. This time, the computer will choose the numbers. e = 19° • d = 0.8 m %3D %3D e = 8 m • M = 2300 kg • Cable's distance from the hinge (5 m in the text) is c = 6.4 m •h = 12 m • Lot's mass (1000 kg in the text) is m = 1200 kg %3D %3D

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Rotational Equilibrium And Rotational Dynamics

In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.

Equilibrium of Forces

The tension created on one body during push or pull is known as force.

Question

11. Sir Lost-a-Lot dons his armor and sets out from the castle on
his trusty steed (Fig. P12.11). Usually, the drawbridge is low-
ered to a horizontal position so that the end of the bridge
rests on the stone ledge. Unfortunately, Lost-a-Lot's squire
didn't lower the drawbridge far enough and stopped it at
20.0° above the horizontal. The knight and his horse
stop when their combined center of mass is d = 1.00 m from
the end of the bridge. The uniform bridge is l = 8.00 m
long and has mass 2 000 kg. The lift cable is attached to the
bridge 5.00 m from the hinge at the castle end and to a
point on the castle wall h = 12.0 m above the bridge. Lost-a-
Lot's mass combined with his armor and steed is 1 000 kg.
Determine (a) the tension in the cable and (b) the horizon-
tal and (c) the vertical force components acting on the
bridge at the hinge.
h

Problem 11b asks for the x-component of the force
on the bridge due to the hinge. Answer in
Newtons. This time, the computer will choose the
numbers.
• 0 = 19°
• d = 0.8 m
%3D
• e = 8 m
%3D
M = 2300 kg
%3D
Cable's distance from the hinge (5 m in the text)
is c = 6.4 m
• h = 12 m
• Lot's mass (1000 kg in the text) is m = 1200 kg
%3D

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