Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
Problem 11.6: Determine the capacitor rating in KVAR and also in farad to improve the load pf from 0.75 lagging to 0.95 lagging at a 3-phase, 60 Hz, 480 V distribution point delivering 2400 kW real power. Also determine the simple payback period for the capacitor cost. Assume that the motor runs for 400 hours per month, the utility demand charge is $15 per kVA, energy charge is $0.15 per kWh, capacitor cost is $70 per KVAR installed, and cable power loss is 1% per phase.

Problem 11.6: Determine the capacitor rating in KVAR and also in farad to improve the load pf from 0.75 lagging to 0.95 lagging at a 3-phase, 60 Hz, 480 V distribution point delivering 2400 kW real power. Also determine the simple payback period for the capacitor cost. Assume that the motor runs for 400 hours per month, the utility demand charge is $15 per kVA, energy charge is $0.15 per kWh, capacitor cost is $70 per KVAR installed, and cable power loss is 1% per phase.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
Problem 11.6: Determine the capacitor rating in kVAR and also in farad to improve the load pf from 0.75 lagging to 0.95 lagging at a 3-phase, 60 Hz, 480 V distribution point delivering 2400 kW real power. Also determine the simple payback period for the capacitor cost. Assume that the motor runs for 400 hours per month, the utility demand charge is $15 per kVA, energy charge is $0.15 per kWh, capacitor cost is $70 per kVAR installed, and cable power loss is 1% per phase.
Transcribed Image Text:Problem 11.6: Determine the capacitor rating in kVAR and also in farad to improve the load pf from 0.75 lagging to 0.95 lagging at a 3-phase, 60 Hz, 480 V distribution point delivering 2400 kW real power. Also determine the simple payback period for the capacitor cost. Assume that the motor runs for 400 hours per month, the utility demand charge is $15 per kVA, energy charge is $0.15 per kWh, capacitor cost is $70 per kVAR installed, and cable power loss is 1% per phase.
Expert Solution
steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS