Problem 11.5. Let X1, X2,..., Xn be a random sample from an exponential distribution with an unknown mean 0. Consider these as individual, unmodified data. What is the expression for the maximum likelihood estimator of 0 denoted by OMLE?
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- . Given a normal random variable X with mean μ = 100 and variance o² = 49 if we randomly observe X=30, is this an unusual observation? (a) This would be an unusual observation because it lies less than 3 standard deviations away from the mean. (b) This would not be an unusual observation because it lies less than 3 standard deviations away from the mean. (c) This would be an unusual observation because it lies more than 3 standard deviations away from the mean. (d) This would not be an unusual observation because it lies more than 3 standard deviations away from the mean.The third worksheet labeled sample B is a simple random sample with replacement, with seven observations in the sample, from some population. The index i in the first column is just an integer name for each observation. The specific values x in the second column are measures of a random variable X distributed in the population. Now suppose this random variable X is known to have a Normal distribution in the sampled population. You still do not know the population mean and must estimate it from the sample, as you did earlier. BUT NOW, in this question, you know that the population standard deviation of the random variable X is 4. Compute the upper bound of an 80% confidence interval for the population mean, using the appropriate sample estimate and techniques appropriate to the new knowledge situation described above. i xi 1 74.2 2 72.79 3 70.35 4 74.37 5 73.34 6 78.96 7 77.9915. A random variable X has a mean ? = 10 and a variance ? 2 = 4. Using Chebychev’s inequality, find:(a) ?(|? − 10| ≥ 3)
- 1.6. Show that 1 s2 E1(Xi – x)² is unbiased estimator of the population variance o? i=1 п-1The third worksheet labeled sample B is a simple random sample with replacement, with seven observations in the sample, from some population. The index i in the first column is just an integer name for each observation. The specific values x in the second column are measures of a random variable X distributed in the population. Now suppose this random variable X is known to have a Normal distribution in the sampled population. You still do not know the population mean and must estimate it from the sample, as you did earlier. BUT NOW, in this question, you know in advance that the true population standard deviation of the random variable X is 4. Compute the standard error (of the sample mean), given this new knowledge situation. i xi 1 74.2 2 72.79 3 70.35 4 74.37 5 73.34 6 78.96 7 77.99
- 5.STATISTICAL INFERENCE9. This is a simplified inventory problem. Suppose that it costs c dollars to stock anitem and that the item sells for s dollars. Suppose that the number of items thatwill be asked for by customers is a random variable with the frequency functionp(k). Find a rule for the number of items that should be stocked in order tomaximize the expected income. (Hint: Consider the difference of successiveterms.)The third worksheet labeled sample B is a simple random sample with replacement, with seven observations in the sample, from some population. The index i in the first column is just an integer name for each observation. The specific values x in the second column are measures of a random variable X distributed in the population. Now suppose this random variable X is known to have a Normal distribution in the sampled population, BUT you do not know the population mean or the population standard deviation of that Normal distribution: Both must be estimated from the sample as you just did. Compute the lower bound of an 80% confidence interval for the population mean, using the appropriate sample estimates and techniques appropriate to the knowledge situation described above. i xi 1 74.2 2 72.79 3 70.35 4 74.37 5 73.34 6 78.96 7 77.99
- 25. Each of a random sample of 30 student nurses who participated in a research project was given a test designed to measure the degree of creative thinking. The standard deviation of the scores was 11. Can one conclude from these data that the population variance is less than 400? Let α = 0. 05 and assume that the population is normally distributed. (A) Yes (B) No34) If a population exhibits a skew of -5.00 and an excess kurtosis of 5.00 which of the following is true? The population mean exceeds the median. The population variance exceeds the standard deviation. The population standard deviation exceeds the variance. The population median equals the mean. The population median exceeds the mean.