Problem 11 یے A 40° 90N 0.5 m 37° 80N 0.5 m 70N 30° B 50N 60N Calculate the net torque acting on the rod shown in the figure. Assume that the system is pivoted about point B (the right end). Problem 12 Repeat the previous problem assuming that the rod is pivoted about its center.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem 11**

There is a diagram featuring a horizontal rod labeled with points A and B. The rod is 1 meter long, divided equally into two segments of 0.5 meters each. Four forces are acting on the rod:

1. A 90N force at a 40° angle to the left of point A.
2. An 80N force at a 37° angle to the right of point A.
3. A 60N force directed downward at the middle of the rod.
4. A 70N force at a 30° angle to the right of point B.
5. A 50N force directed to the right from point B.

Calculate the net torque acting on the rod, assuming the system is pivoted about point B (the right end).

**Problem 12**

Repeat the previous problem, assuming that the rod is pivoted about its center.
Transcribed Image Text:**Problem 11** There is a diagram featuring a horizontal rod labeled with points A and B. The rod is 1 meter long, divided equally into two segments of 0.5 meters each. Four forces are acting on the rod: 1. A 90N force at a 40° angle to the left of point A. 2. An 80N force at a 37° angle to the right of point A. 3. A 60N force directed downward at the middle of the rod. 4. A 70N force at a 30° angle to the right of point B. 5. A 50N force directed to the right from point B. Calculate the net torque acting on the rod, assuming the system is pivoted about point B (the right end). **Problem 12** Repeat the previous problem, assuming that the rod is pivoted about its center.
Expert Solution
Step 1

11)

Determine the net torque on the rod when the system is pivoted at point B.

τB=[(90 N)sin40°](0.5 m+0.5 m)+[(80 N)sin37°](0.5 m)(60 N)(0.5 m)τB=51.92 Nm  (clockwise)

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