est 2 Practice xTechlExpressB Homepage - Tennessee Technolo x202%20Practice%20Problems.pdf身司6 / 6土100%Problem 11: Determine the magnitude of P for the crankshaft to be in equilibrium. Alsodetermine the reactions at A and B. Point A is a journal bearing and point B is athrust bearing. (Hint: both bearings only exert force reactions on the crankshaft.)Ans. P = 100 lb, Ax = 136 lb, Az = 40 lb, Bx = -35.7 lb, Bz = 40 lb, By = 0 lb%3D80 Ib10 in.yB.14 in.14 in.6 in.8 in.4in.The plate has a weight of W with center of gravity G. Determine the distance, d.alono line GH where the vertical force P-0 75W will eanse the tension in cahleProblem 12:Show all9:49 PMN52°F Clearヘ画(x10/27/2021hp12def9144hoIIinsertprt scts10fa4+トト&backspace

Answered: Image /qna-images/answer/968d24e5-682d-4df5-8b94-b94887f8719c.jpg

Answered: Problem 11: Determine the magnitude of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The shaft pulley system has a universal joint at point 0. So it is supported by a slide at point A bearing and fixed support at point C. There is a mass of 12kg on the pulley and subject to the belt tensions but the mass of the shaft is negligible. a) what is the static equilibrium equations for the assembly. b) draw the FBD of the assembly. c) show the assembly and the FBD for the components
Draw FBD, write equilibrium equations for the assembly and calculate reaction forces for internal and external joints
What is the right answer and solution?
Correct solution will be liked..
Problem 8 Another Gear Two disks are connected to one another with a belt as shown. Both disks have mass m but the larger one has radius 4R and the smaller has radius R. The larger disk is powered by a motor that produces a constant torque, To, in the counter- clockwise direction. (a) By using the rotational equivalent of Newton's laws on the larger disk show that the difference in the tension at the top with the tension at the bottom is: Tto - Thot 1 4R (TO - 2m Ra), where a is the linear accleration of the elt. (b) Do the same (find Ttop - Tbot) with the smaller disk. (c) Use your two expressions to find the gular acceleration of the smaller disk. You answer should have m, R, and To in it only. (Careful, the sr aller disk does not have the same angular acceleration as the larger one).
4/4 Calculate the forces in members BE and BD of the loaded trusu. B 8 8 E D 1000 Ib Problem 4/4
Question 3) The position of the head and neck and the forces acting on the head are shown in the figure. The center of gravity of the head of mass m=8 kg is located at point C. The joint reaction force of FJ=147 N, which makes an angle of α= 42° with the vertical from the point B, is acting on the skull by the neck extensor muscles. The center of the atlantooccipital joint is located at point B. For this flexion position of the head, FM neck muscle force, which makes an angle of γ with the horizontal from the A point, is effective. (Take the gravitational acceleration g as 9.81 m/s2). Accordingly; a) Calculate the angle γ of the FM muscle strength with the horizontal. b) Calculate the FM muscle strength. (Write your result in N.) Answer
Downvote if it is handwritten. So only answer this typewritten to get an upvote. Make sure it is correct too.
Create a statics problem east to solve. With equilibrium and a couple of reaction forces. With its respect free body diagram. Thanks
Need help on all questions. Please include all units, steps to the problem and information such as its direction or if it is in compression or tension. Thx.
2m dz - m. None of them اپن For the robot above, please determine Uo (the potential energy of Link #0) OU 9.8 OU = 5.6 OUo = 4,9 OU=19.6 * d₁, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg.m². The mass centers are located on the middle point of each link.
NAME Question 1 (6/20) ANSWER ON THE YELLOW PAGES The nose wheel of the landing gear of an aircraft is extended and retracted by applying a torque M to the rod BC by means of an shaft located at point B. The rod AO, on which the landing wheel is also located, has a combined mass of 100 kg which may be simplified to a point force at point G. The masses of the bars CD and BC may be neglected. If the point D is located underneath point B, the rod CD is at an angle of 30° to the vertical y-axis. At this position the landing gear should be kept stationary, dynamic effects may therefore be neglected. All components are made out of stainless steel with max=200 MPa and Imax = 75 MPa. ALO d. 800 mm 400 mm 200 mm B 300 D M 500 mm OC 500 mm A D Questions, also draw all relevant free-body diagrams: a. Calculate the magnitude of the reaction force at point A. b. Calculate the minimum diameter of the pin in point A. The connection in point A is realized as shown on the right figure. Use a safety…

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