Problem 1.11 A large steel plate under uniform applied tensile stress contains two cracks, both of which are remote from the edges of the plate and from each other. One is 12 mm in length and is inclined at an angle a= 30°, the other is 15 mm in length and is inclined at an angle B= 45° (figure 1.15). The steel has fracture toughness of Kie = 23 MPa/m and Ke=15 MPa/m. a) Calculate the fracture stress of the plate and state which of the two cracks will cause failure and in which failure mode. (1) པ། Figure 1.15: Finite width thin plate under uniform applied smile stress with two cracks

What is a typical voltage used for capillary zone electrophoresis? a. 2.5 MV b. 250 kV c. 250 MV d. 25 V e. 2.5 kV f. 25 MV g. 250 V h. 25 kV

Question 1 Select all that apply. Which of the following are considered to be "core losses"? 12R heating loss Flux lines that bulge out at core gaps Currents that circulate within the machine non-ferrous components Field Lines that circulate around conductors and coils Rapid Changes in Domain orientation

A flux of 0.0016 Wb flows in a silicon sheet steel coil/core. The arrangement appears as shown below with the following dimensions: Ac = 0.0025 m? Core/gap area: Flux path length: le = 0.350 m lg = 0.0015 m N = 500 Air gap length: Number of turns: %3D A. What is the current, I, through the winding? B. What is the energy stored in the inductance? C. Assume that the current is given by i =9.75 sin (3147) A. What is the RMS voltage that would appear across the winding? D. Assume that the gap is removed from the arrangement with the flux path remaining at 0.350 m. For a flux of 0.0016 Wb, what is the inductance of the arrangement? E. What is the energy stored in the inductance with the gap removed?