Problem 1. Solve the following IVPS using LT method. 1) y" – 10y + 25y = 8e-", y(0) = 1, y'(0) = -4; -2t %3| 2) y" – 10y + 25y = 24te-", y(0) = -2, y'(0) = -10; %3D 3) y" + 16y = 1, y(0) = 1, y'(0) = 2; %3D 4) y – 4y = 8u(t – 3), y(0) = 2; %3D 5) y" – 2y' + y = 8(t – 1) y(0) = 3, y(0) = –4. %3D
Problem 1. Solve the following IVPS using LT method. 1) y" – 10y + 25y = 8e-", y(0) = 1, y'(0) = -4; -2t %3| 2) y" – 10y + 25y = 24te-", y(0) = -2, y'(0) = -10; %3D 3) y" + 16y = 1, y(0) = 1, y'(0) = 2; %3D 4) y – 4y = 8u(t – 3), y(0) = 2; %3D 5) y" – 2y' + y = 8(t – 1) y(0) = 3, y(0) = –4. %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Do question 1
![Problem 1.
Solve the following IVPS using LT method.
1) y" – 10y' + 25y
%3D 8e -2", у(0) -
y(0) = 1,
y'(0) = -4;
2) y" – 10y' + 25y
= 24te-2t, y(0) = –2, y'(0) = –10;
3) y" + 16y = 1, y(0) = 1, y'(0) = 2;
4) y' – 4y = 8u(t – 3), y(0) = 2;
5) y" – 2y' + y = 8(t – 1) y(0) = 3,
y'(0) = -4.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12ec4fa0-2f77-4de2-b987-931c4337bd53%2F301e7f02-9a6d-460f-95eb-22595662292c%2Fb2ru9mp_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 1.
Solve the following IVPS using LT method.
1) y" – 10y' + 25y
%3D 8e -2", у(0) -
y(0) = 1,
y'(0) = -4;
2) y" – 10y' + 25y
= 24te-2t, y(0) = –2, y'(0) = –10;
3) y" + 16y = 1, y(0) = 1, y'(0) = 2;
4) y' – 4y = 8u(t – 3), y(0) = 2;
5) y" – 2y' + y = 8(t – 1) y(0) = 3,
y'(0) = -4.
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