PROBLEM 1. A hollow cylindrical steel shaft is 1.5 m long and has inner and outer diameters respectively equal to 40 and 60 mm. a) What is the largest torque that can be applied to the shaft 60 mm if the shearing stress is not to exceed 120 MPa? b) What torque should be applied to the end of the shaft to produce an angle of twist of 2 degrees? Modulus of rigidity of 40 mm 1.5 m steel is 77 GPa.
PROBLEM 1. A hollow cylindrical steel shaft is 1.5 m long and has inner and outer diameters respectively equal to 40 and 60 mm. a) What is the largest torque that can be applied to the shaft 60 mm if the shearing stress is not to exceed 120 MPa? b) What torque should be applied to the end of the shaft to produce an angle of twist of 2 degrees? Modulus of rigidity of 40 mm 1.5 m steel is 77 GPa.
Chapter2: Loads On Structures
Section: Chapter Questions
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1.
A hollow cylindrical steel shaft is 1.5 m long and has inner and outer diameters respectively equal to 40 and 60 mm.
a) What is the largest torque that can be applied to the shaft if the shearing stress is not to exceed 120 MPa?
b) What torque should be applied to the end of the shaft to produce an angle of twist of 2 degrees? Modulus of rigidity of steel is 77 GPa.
Transcribed Image Text:PROBLEM 1.
A hollow cylindrical steel shaft is 1.5 m long and has inner and
outer diameters respectively equal to 40 and 60 mm.
a) What is the largest torque that can be applied to the shaft
if the shearing stress is not to exceed 120 MPa?
60 mm
b) What torque should be applied to the end of the shaft to
40 mm
produce an angle of twist of 2 degrees? Modulus of rigidity of
1.5 m
steel is 77 GPa.
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