PROBLEM 1: Steady state has been reached prior to t = 0 in the circuit below. Assume Vs(t) = 21.2V, Is(t) = 12 mA, R₁ = 100 S2, R₂ = 200 S2, R3 = 300 S2, R4 = 400 S2, Rs = 500 2, R6 = 600 S2, R7 = 700 £2, and L = 0.42 H. (a) Find the expression for the complete response of the inductor current iL(t) for t≥ 0 (b) Sketch the waveform for iL(t), labeling and providing values for the initial value, final value, time to reach steady state, and initial slope of the characteristic at t=0 L dilt) + 1₂ (t) = 0 Tan dt Vs(t)( R₁ t = 0 R₂ R3 www R4 R5 i(t) Is(t) t = 07 R7 R6 bas V₂ (f): < dicht) dt L.

Introductory Circuit Analysis (13th Edition)
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**Problem 1:**

Steady state has been reached prior to \( t = 0 \) in the circuit below. Assume \( V_s(t) = 21.2 \, \text{V} \), \( I_s(t) = 12 \, \text{mA} \), \( R_1 = 100 \, \Omega \), \( R_2 = 200 \, \Omega \), \( R_3 = 300 \, \Omega \), \( R_4 = 400 \, \Omega \), \( R_5 = 500 \, \Omega \), \( R_6 = 600 \, \Omega \), \( R_7 = 700 \, \Omega \), and \( L = 0.42 \, \text{H} \).

### (a) 
Find the expression for the **complete response** of the inductor current \( i_L(t) \) for \( t \geq 0 \).

### (b) 
Sketch the waveform for \( i_L(t) \), labeling and providing values for the initial value, final value, time to reach steady state, and initial slope of the characteristic at \( t = 0 \).

#### Circuit Diagram:

- **Components:**
  - Voltage source \( V_s(t) \).
  - Inductor \( L \).
  - Seven resistors labeled \( R_1, R_2, \ldots, R_7 \).
  
- **Configuration:**
  - The circuit includes a combination of series and parallel resistors and an inductor. 
  - The switch is closed at \( t = 0 \).

#### Equations:

1. \( \frac{L}{R_{\text{eq}}} \frac{di_L(t)}{dt} + i_L(t) = 0 \)

2. \( V_L(t) = L \frac{di_L(t)}{dt} \)

- These equations govern the behavior of the inductor current \( i_L(t) \) over time, describing its transient response.

**Note:** The diagram shows the arrangement of resistors and the inductor in the circuit, which influences the transient and steady-state behavior of \( i_L(t) \).
Transcribed Image Text:**Problem 1:** Steady state has been reached prior to \( t = 0 \) in the circuit below. Assume \( V_s(t) = 21.2 \, \text{V} \), \( I_s(t) = 12 \, \text{mA} \), \( R_1 = 100 \, \Omega \), \( R_2 = 200 \, \Omega \), \( R_3 = 300 \, \Omega \), \( R_4 = 400 \, \Omega \), \( R_5 = 500 \, \Omega \), \( R_6 = 600 \, \Omega \), \( R_7 = 700 \, \Omega \), and \( L = 0.42 \, \text{H} \). ### (a) Find the expression for the **complete response** of the inductor current \( i_L(t) \) for \( t \geq 0 \). ### (b) Sketch the waveform for \( i_L(t) \), labeling and providing values for the initial value, final value, time to reach steady state, and initial slope of the characteristic at \( t = 0 \). #### Circuit Diagram: - **Components:** - Voltage source \( V_s(t) \). - Inductor \( L \). - Seven resistors labeled \( R_1, R_2, \ldots, R_7 \). - **Configuration:** - The circuit includes a combination of series and parallel resistors and an inductor. - The switch is closed at \( t = 0 \). #### Equations: 1. \( \frac{L}{R_{\text{eq}}} \frac{di_L(t)}{dt} + i_L(t) = 0 \) 2. \( V_L(t) = L \frac{di_L(t)}{dt} \) - These equations govern the behavior of the inductor current \( i_L(t) \) over time, describing its transient response. **Note:** The diagram shows the arrangement of resistors and the inductor in the circuit, which influences the transient and steady-state behavior of \( i_L(t) \).
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