Problem 1 Given: BC = DC ; AC = EC ee Prove: ABCA = ADCE E

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter1: Expressions And Functions
Section: Chapter Questions
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Answer the first question just like the second picture. 

Problem 1
B
Given: BC = DC ; AC = EC
ee
Prove: ABCA = ADCE
E
Transcribed Image Text:Problem 1 B Given: BC = DC ; AC = EC ee Prove: ABCA = ADCE E
Given: AC = CB
CD Bisects AB
Prove: AADC = ABDC
A
D
B
Given: AC = CB
CD Bisects AB
Prove: AADC = ABDC
A
D
B
Transcribed Image Text:Given: AC = CB CD Bisects AB Prove: AADC = ABDC A D B Given: AC = CB CD Bisects AB Prove: AADC = ABDC A D B
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