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Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard P(x) 0.033 1 0.163 2 0.304 deviation. If a probability distribution is not given, identify the requirements 0.304 that are not satisfied. 4 0.163 0.033 ..... Does the table show a probability distribution? Select all that apply. A. Yes, the table shows a probability distribution. B. No, the random variable x is categorical instead of numerical. C. No, the random variable x's number values are not associated with probabilities. D. No, not every probability is between 0 and 1 inclusive. E. No, the sum of all the probabilities is not equal to 1. O OO D

Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard P(x) 0.033 1 0.163 2 0.304 deviation. If a probability distribution is not given, identify the requirements 0.304 that are not satisfied. 4 0.163 0.033 ..... Does the table show a probability distribution? Select all that apply. A. Yes, the table shows a probability distribution. B. No, the random variable x is categorical instead of numerical. C. No, the random variable x's number values are not associated with probabilities. D. No, not every probability is between 0 and 1 inclusive. E. No, the sum of all the probabilities is not equal to 1. O OO D

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Title: Probability Distribution Analysis of X-linked Genetic Disorder in Children** **Introduction:** Five males with an X-linked genetic disorder have one child each. The random variable \( x \) represents the number of children among the five who inherit the X-linked genetic disorder. This study explores whether the given set of data forms a probability distribution, and if so, calculates its mean and standard deviation. If it does not form a probability distribution, we identify the unsatisfied requirements. **Data Table:** | \( x \) | \( P(x) \) | |---------|------------| | 0 | 0.033 | | 1 | 0.163 | | 2 | 0.304 | | 3 | 0.304 | | 4 | 0.163 | | 5 | 0.033 | **Analysis:** To determine if the table represents a probability distribution, certain criteria must be met: 1. All probabilities \( P(x) \) must be between 0 and 1 inclusive. 2. The sum of all probabilities must equal 1. **Checklist:** - Does the table show a probability distribution? Select all that apply. - A. Yes, the table shows a probability distribution. - B. No, the random variable \( x \) is categorical instead of numerical. - C. No, the random variable \( x \)'s number values are not associated with probabilities. - D. No, not every probability is between 0 and 1 inclusive. - E. No, the sum of all the probabilities is not equal to 1. **Conclusion:** This detailed analysis helps in understanding if the given data correctly represents a probability distribution and aids in further statistical calculations involving genetic disorders.
Transcribed Image Text:**Title: Probability Distribution Analysis of X-linked Genetic Disorder in Children** **Introduction:** Five males with an X-linked genetic disorder have one child each. The random variable \( x \) represents the number of children among the five who inherit the X-linked genetic disorder. This study explores whether the given set of data forms a probability distribution, and if so, calculates its mean and standard deviation. If it does not form a probability distribution, we identify the unsatisfied requirements. **Data Table:** | \( x \) | \( P(x) \) | |---------|------------| | 0 | 0.033 | | 1 | 0.163 | | 2 | 0.304 | | 3 | 0.304 | | 4 | 0.163 | | 5 | 0.033 | **Analysis:** To determine if the table represents a probability distribution, certain criteria must be met: 1. All probabilities \( P(x) \) must be between 0 and 1 inclusive. 2. The sum of all probabilities must equal 1. **Checklist:** - Does the table show a probability distribution? Select all that apply. - A. Yes, the table shows a probability distribution. - B. No, the random variable \( x \) is categorical instead of numerical. - C. No, the random variable \( x \)'s number values are not associated with probabilities. - D. No, not every probability is between 0 and 1 inclusive. - E. No, the sum of all the probabilities is not equal to 1. **Conclusion:** This detailed analysis helps in understanding if the given data correctly represents a probability distribution and aids in further statistical calculations involving genetic disorders.
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