Problem 1: A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 6.5 cm and accelerates at the rate of 7.5 rad/s2 , and it is in contact with the pottery wheel (radius 24.0 cm ) without slipping. Part A Calculate the angular acceleration of the pottery wheel. Part B Calculate the time it takes the pottery wheel to reach its required speed of 70 rpm .
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
Problem 1: A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 6.5 cm and accelerates at the rate of 7.5 rad/s2 , and it is in contact with the pottery wheel (radius 24.0 cm ) without slipping.
Part A
Part B
Trending now
This is a popular solution!
Step by step
Solved in 2 steps