Pls answer in complete;No rounding off decimals. Round off only in final answer up to 3 Problem 1Given:FH30°30°Mass of canister: 4000 kgMass of beam BD:50 kgBEMax allowable force:0.3 m0.4 m0.3 m1. AB = 30 kN2. CD = 30 kNPc3. EF = 34 kN4. GH = 34 kNDetermine the greatest allowable acceleration of the system.

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Problem 1 a Given: H 30 30° Mass of canister: 4000 kg Mass of beam BD: 50 kg B Max allowable force: 0.3 m 0.4 m 0.3 m 1. AB = 30 kN 2. CD = 30 kN 3. EF = 34 kN 4. GH 34 kN %3D Determine the greatest allowable acceleration of the system.

Problem 1 a Given: H 30 30° Mass of canister: 4000 kg Mass of beam BD: 50 kg B Max allowable force: 0.3 m 0.4 m 0.3 m 1. AB = 30 kN 2. CD = 30 kN 3. EF = 34 kN 4. GH 34 kN %3D Determine the greatest allowable acceleration of the system.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Pls answer in complete;

No rounding off decimals. Round off only in final answer up to 3

Problem 1
Given:
F
H
30°
30°
Mass of canister: 4000 kg
Mass of beam BD:
50 kg
B
E
Max allowable force:
0.3 m
0.4 m
0.3 m
1. AB = 30 kN
2. CD = 30 kN
Pc
3. EF = 34 kN
4. GH = 34 kN
Determine the greatest allowable acceleration of the system.

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