Problem 1: A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 200m on one side of the vertex of the straight grade and 100m on the other. The station of the beginning of the curve (200m side) is 10+ 000 and its elevation is 228m. a.) Determine the elevation at station 10 + 040. b.) If the uphill edge of the underside of the bridge is at station 10+ 220 and at elevation 229.60m, what is the vertical clearance under the bridge at this point? c.) Determine the stationing of the lowest point of the curve. P..C. 10+000 Fl. 228 m 40 -200 81=-38 10+040 B H -100 8 +59 8=(500+£0 3001 -

Problem 1: A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 200m on one side of the vertex of the straight grade and 100m on the other. The station of the beginning of the curve (200m side) is 10+ 000 and its elevation is 228m. a.) Determine the elevation at station 10 + 040. b.) If the uphill edge of the underside of the bridge is at station 10+ 220 and at elevation 229.60m, what is the vertical clearance under the bridge at this point? c.) Determine the stationing of the lowest point of the curve. P..C. 10+000 Fl. 228 m 40 -200 81=-38 10+040 B H -100 8 +59 8=(500+£0 3001 -

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Sag Curve: A grade from the PVC to the PVI is -6% and from PVI to PVT is +2%. It is required to connect these grade lines with a vertical parabolic curve will pass 3.0 m. directly above the PVI. 11. Determine the length of this curve. a) 420 m b) 380 m c) 400 m d) 300 m 12. Determine the location of the lowest point measured from the PVT. a) 100m b) 75m c) 100m d) 225m 13. Compute the vertical offset at a point on the curve 100m from the PVC. a) 2.45m b) 2.33m c) 1.56m d) 1.33m
A 400m vertical curve joins a +2.70% grade with a -1.50% grade. The PVI is at station 1+500 and elevation 25.00m. The station and elevation at PVC are ?
b) A 400 m vertical curve connects a -2% grade with a +4% grade. The P.I. is located at chainage 150 meters with an altitude of 29 meters above sea level. Calculate the elevation of the lowest point on the vertical curve.
Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation (1291.2 m). the back grade of (-8%) meet the forward grade of (+7.8%) at (PVI) station (54+00) with elevation (1281.5 m). determine the length of the curve with the stations of (PVC) and (PVT)? PVT PVC g₁=(-6%) PVI g₂=(+5.8%)
1.) A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 240m on one side of the vertex of the straight grade and 115m on the other. The station of the beginning of the curve, PC, is 18 + 612 and its elevation is 415.81m. a. Determine the elevation at station 18 + 672. b. Determine the stationing of the lowest point of the curve.
A 532m equal tangent crest vertical curve has PVC at Sta 19+284 and at elevation 181m. The initial grade is 3.02% and the final grade is -4.37%. Determine the elevation (m) of PVI.
2. There is a Vertical Curve with a length of 300 feet, a g1 of -3.2%, a g2 of 1.8%, a PVI at station 20+50.00, at an elevation of 365.92. Determine the HP/LP and elevate all even 100 foot stations and the HP / LP.
A -2.5% grade is connected to a +1.0% grade by means of 180 m vertical curve. The PI station and elevation is 10 + 000 and 100 m above sea level respectively. What is the station of the lowest point on the vertical curve?
A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVC
A 627m equal tangent crest vertical curve has PVC at Sta 17+579 and at elevation 155m. The initial grade is 4.49% and the final grade is -6.82%. Determine the station of PVI.
A-6.5% grade is followed by a 1.75% grade intersecting at Sta. 15+750, with an elevation of 385.5 m. The change of grade is restricted to 0.5% per 20 m station. Compute the elevation of Sta. 15+710