2. There is a Vertical Curve with a length of 300 feet, a g1 of -3.2%, a g2 of 1.8%, a PVI at station 20+50.00, at an elevation of 365.92. Determine the HP/LP and elevate all even 100 foot stations and the HP/LP.

2. There is a Vertical Curve with a length of 300 feet, a g1 of -3.2%, a g2 of 1.8%, a PVI at station 20+50.00, at an elevation of 365.92. Determine the HP/LP and elevate all even 100 foot stations and the HP/LP.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

SITUATION. A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 200-m on one side of the vertex of the straight grade and 100-m on the other. The station of the beginning of the curve (200-m side) is 10+000 and its elevation is 228 m. If the uphill edge of the underside of the bridge is at station 10+220 and at elevation 229.206 m, what is the vertical clearance under the bridge at this point?
A 400m vertical curve joins a +2.70% grade with a -1.50% grade. The PVI is at station 1+500 and elevation 25.00m. The station and elevation at PVC are ?
b) A 400 m vertical curve connects a -2% grade with a +4% grade. The P.I. is located at chainage 150 meters with an altitude of 29 meters above sea level. Calculate the elevation of the lowest point on the vertical curve.
A spiral 80m long connects a tangent with a 7° 30' circular curve. If the stationing of the T.S. is 12+000,and the gauge of the tract on the curve is 1.5m.Determine the following:(a) the elevation of the outer rail at the midpoint, if the velocity of the fastest train that can pass over thecurve is 60kph,(b) the spiral angle at the first quarter point,(c) the deflection angle at the end point, and(d) the offset from the tangent at the second quarter point.
Q4: A road is to be redesigned using a parabolic vertical curve to provide clearance beneath a bridge (see Figure below). The (PC OR PVC) has chainage 1140.00m, with an RL of 125.536m. A bridge at chainage 1300.00 has an RL = 128.5m at its lowest point. You must provide 4.5m clearance from the underside of the bridge, and the parabola will finish with a succeeding gradient, G 2=+3.6 %. G1= ? 1. What is the length of the curve? 2. What is the initial gradient G1? PC Ch 1140 RL 125.536 G1= ? L =? Point PVC PVT Easting (m) 122.8 326.1 Here De bridkje Ah = 4.5 Northing (m) Ch 1300 RL 128.5 40.2 76.3 G2 = +3.6% RL = 124.00 PT Elevation 125.536 ?
1.) A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 240m on one side of the vertex of the straight grade and 115m on the other. The station of the beginning of the curve, PC, is 18 + 612 and its elevation is 415.81m. a. Determine the elevation at station 18 + 672. b. Determine the stationing of the lowest point of the curve.
Q4: A road is to be redesigned using a parabolic vertical curve to provide clearance beneath a bridge (see Figure below). The (PC OR PVC) has chainage 1140.00m, with an RL of 125.536m. A bridge at chainage 1300.00 has an RL = 128.5m at its lowest point. You must provide 4.5m clearance from the underside of the bridge, and the parabola will finish with a succeeding gradient, G 2=+3.6 %. G1= ? 3. Find the chainage and RL for the lowest point on the curve. (E PC Ch 1140 RL 125.536 G1= ? L =? Point PVC PVT Easting (m) 122.8 326.1 Here De bridkje Ah = 4.5 Northing (m) Ch 1300 RL 128.5 40.2 76.3 G2 = +3.6% RL = 124.00 PT Elevation 125.536 ?
A 600ft vertical curve has its PVI at elevation 264.96ft. The initial and final grades are 2.1% and -4.2% respectively. Determine the elevation of a point 422ft from PVC. Round your answer to 3 decimal places.
a horizontal curve has a design speed of 45 mph the curve must have a radius of 750 ft if f= 0.12 what should be the superr elevation? please show all step
A sag Vertical curve has a profile elevations @ BC and at distance L/2 are 206 and 202.5 m respectively and the PI elevation is 200 m. Find the following elevation at. a) 0.25L b) 0.75L c) EC Find the Station and elevation of the lowest point.
An equal tangent sag curve is designed with a PVC at station 3+320 and elevation 290m, the PVI at station 3+375 and elevation 288.74m, and the low point is at station 3+365.determine the design speed of the curve.